Tính đạo hàm các hàm số sau: a. $y=(\frac{2x+1}{x-1})^3$ b. $y=(5x^2+4x-1)^4(7x-3)^5$ b. $y=(5x^2+4x-1)^4.(7x-3)^5$

a.

`y’=3.((2x+1)/(x-1))^2.((2x+1)/(x-1))^’`

`y’=3.((2x+1)/(x-1))^2.\frac{(2x+1)'(x-1)-(2x+1)(x-1)’}{(x-1)^2}`

`y’=3.((2x+1)/(x-1))^2.\frac{2(x-1)-(2x+1)}{(x-1)^2}`

`y’=3.((2x+1)/(x-1))^2.\frac{-3}{(x-1)^2}`

`y’=\frac{-9(2x+1)^2}{(x-1)^4}`

b.

`y’=[(5x^2+4x-1)^4]^’.(7x-3)^5+(5x^2+4x-1)^4.[(7x-3)^5]^’`

`y’=4(5x^2+4x-1)^3.(10x+4).(7x-3)^5+(5x^2+4x-1)^4. 5(7x-3)^4 .7`

`y’=(5x^2+4x-1)^3.(7x-3)^4.[4.(10x+4)(7x-3)+35(5x^2+4x-1)]`

`y’=(5x^2+4x-1)^3.(7x-3)^4.(455x^2+132x-83)`