Tính đạo hàm của hàm số sau Y=sin căn 14x^2-14x+14 08/11/2021 Bởi Melody Tính đạo hàm của hàm số sau Y=sin căn 14x^2-14x+14
$y’=\cos\sqrt{14x^2-14x+14}(\sqrt{14x^2-14x+14})’$ $=\cos\sqrt{14x^2-14x+14}.\dfrac{(14x^2-14x+14)’}{2\sqrt{14x^2-14x+14}}$ $=\cos\sqrt{14x^2-14x+14}.\dfrac{28x-14}{2\sqrt{14x^2-14x+14}}$ $=\dfrac{\cos\sqrt{14x^2-14x+14}.(14x-7)}{\sqrt{14x^2-14x+14}}$ Bình luận
y= sin $\sqrt{14x²-14x+14}$ ⇒ y’ = ($\sqrt{14x²-14x+14}$)’ . cos(14x²-14x+14) ⇔y’ = $\frac{(14x²-14x+14)’}{2. \sqrt{14x²-14x+14}}$ . cos(14x²-14x+14) ⇔y’ =$\frac{28x-14}{2. \sqrt{14x²-14x+14}}$. cos(14x²-14x+14) Bình luận
$y’=\cos\sqrt{14x^2-14x+14}(\sqrt{14x^2-14x+14})’$
$=\cos\sqrt{14x^2-14x+14}.\dfrac{(14x^2-14x+14)’}{2\sqrt{14x^2-14x+14}}$
$=\cos\sqrt{14x^2-14x+14}.\dfrac{28x-14}{2\sqrt{14x^2-14x+14}}$
$=\dfrac{\cos\sqrt{14x^2-14x+14}.(14x-7)}{\sqrt{14x^2-14x+14}}$
y= sin $\sqrt{14x²-14x+14}$
⇒ y’ = ($\sqrt{14x²-14x+14}$)’ . cos(14x²-14x+14)
⇔y’ = $\frac{(14x²-14x+14)’}{2. \sqrt{14x²-14x+14}}$ . cos(14x²-14x+14)
⇔y’ =$\frac{28x-14}{2. \sqrt{14x²-14x+14}}$. cos(14x²-14x+14)