Tính đạo hàm của hs sau y=16x^100+16x^50-16x^2-16√x+16x-16 10/11/2021 Bởi Amara Tính đạo hàm của hs sau y=16x^100+16x^50-16x^2-16√x+16x-16
$(16x^{100}+16x^{50}-16x^2-16√x+16x-16)’$ = $100.16x^{99}+50.16x^{49}-2.16x-\dfrac{16}{2√x}+16$ = $1600x^{99}+800x^{49}-32x-\dfrac{16}{2√x}+16$ Bình luận
$y’=(16x^{100})’+(16x^{50})’-(16x^2)’-(16\sqrt{x})’+(16x)’-16’$ $=100.16x^{99}+50.16.x^{49}-2.16x-\dfrac{16}{2\sqrt{x}}+16$ $=1600x^{99}+800x^{49}-32x-\dfrac{8}{\sqrt{x}}+16$ Bình luận
$(16x^{100}+16x^{50}-16x^2-16√x+16x-16)’$
= $100.16x^{99}+50.16x^{49}-2.16x-\dfrac{16}{2√x}+16$
= $1600x^{99}+800x^{49}-32x-\dfrac{16}{2√x}+16$
$y’=(16x^{100})’+(16x^{50})’-(16x^2)’-(16\sqrt{x})’+(16x)’-16’$
$=100.16x^{99}+50.16.x^{49}-2.16x-\dfrac{16}{2\sqrt{x}}+16$
$=1600x^{99}+800x^{49}-32x-\dfrac{8}{\sqrt{x}}+16$