Tính giá trị biểu thức A=(20.212121-202020.21).(1+2+3+…+2021) 18/08/2021 Bởi Athena Tính giá trị biểu thức A=(20.212121-202020.21).(1+2+3+…+2021)
`A = ( 20 . 212121 – 202020 . 21 ) . ( 1 + 2 + 3 + …. + 2021 )` `A = ( 20 . 21 . 10101 – 20 . 10101 . 21 ) . ( 1 + 2 + 3 + … + 2021 )` `A = 0 . ( 1 + 2 + 3 + … + 2021 )` `A = 0` Bình luận
`A=(20.212121-202020.21).(1+2+3+…+2021)` $Ta$ $có:$ ` `(20.212121-202020.21)` `= 21. 10101.20 – 20.10101.21` `=0` `⇒A= 0. (1+2+3+…+2021)` `⇒A=0` Bình luận
`A = ( 20 . 212121 – 202020 . 21 ) . ( 1 + 2 + 3 + …. + 2021 )`
`A = ( 20 . 21 . 10101 – 20 . 10101 . 21 ) . ( 1 + 2 + 3 + … + 2021 )`
`A = 0 . ( 1 + 2 + 3 + … + 2021 )`
`A = 0`
`A=(20.212121-202020.21).(1+2+3+…+2021)`
$Ta$ $có:$ `
`(20.212121-202020.21)`
`= 21. 10101.20 – 20.10101.21`
`=0`
`⇒A= 0. (1+2+3+…+2021)`
`⇒A=0`