Tính giá trị của các biểu thức sau 9^3.8^4/ 6^9.4^2 9^5. 27^3 / 3^18 ( 4/15 : 0,4) : (1,254)^0 giúp mình 3 câu này nha 09/07/2021 Bởi Charlie Tính giá trị của các biểu thức sau 9^3.8^4/ 6^9.4^2 9^5. 27^3 / 3^18 ( 4/15 : 0,4) : (1,254)^0 giúp mình 3 câu này nha
$\frac{9³.8^{4}}{6^{9}.4^{2}}=\frac{3^{6}.2^{12}}{3^{9}.2^{9}.2^{4}}=\frac{3^{6}.2^{12}}{3^{9}.2^{13}}=\frac{1}{3^{3}.2}=\frac{1}{54}$ $\frac{9^{5}.27^{3}}{3^{18}}=\frac{3^{10}.3^{9}}{3^{18}}=\frac{3^{19}}{3^{18}}=3$ $(\frac{4}{15}:0,4):1,254^{0}=(\frac{4}{15}:\frac{2}{5}):1=\frac{4}{15}×\frac{5}{2}=\frac{2}{3}$ Bình luận
`a)(9³.8^4)/(6^9. 4²)=((3^2)^3.(2^3)^4)/((2.3)^9.(2^2)^2)=(3^6. 2^12)/(2^9 .3^9 .2^4)=(3^6. 2^12)/(2^13 .3^9)=1/(2.3^3)=1/(2.27)=1/54` `b)(9^5 .27^3)/(3^18)=((3^2)^5.(3^3)^3)/(3^18)=(3^10 .3^9)/3^18=3^19/3^18=3` `c)(4/15:0,4):(1,254)^0=(4/15:2/5):1=(4/15 . 5/2).1=2/3` Bình luận
$\frac{9³.8^{4}}{6^{9}.4^{2}}=\frac{3^{6}.2^{12}}{3^{9}.2^{9}.2^{4}}=\frac{3^{6}.2^{12}}{3^{9}.2^{13}}=\frac{1}{3^{3}.2}=\frac{1}{54}$
$\frac{9^{5}.27^{3}}{3^{18}}=\frac{3^{10}.3^{9}}{3^{18}}=\frac{3^{19}}{3^{18}}=3$
$(\frac{4}{15}:0,4):1,254^{0}=(\frac{4}{15}:\frac{2}{5}):1=\frac{4}{15}×\frac{5}{2}=\frac{2}{3}$
`a)(9³.8^4)/(6^9. 4²)=((3^2)^3.(2^3)^4)/((2.3)^9.(2^2)^2)=(3^6. 2^12)/(2^9 .3^9 .2^4)=(3^6. 2^12)/(2^13 .3^9)=1/(2.3^3)=1/(2.27)=1/54`
`b)(9^5 .27^3)/(3^18)=((3^2)^5.(3^3)^3)/(3^18)=(3^10 .3^9)/3^18=3^19/3^18=3`
`c)(4/15:0,4):(1,254)^0=(4/15:2/5):1=(4/15 . 5/2).1=2/3`