Tính hợp lý 2[ (95 + 5^11 : 5^10) :2^2 +180] – 2^2 .10^2+2017^0 29/09/2021 Bởi Skylar Tính hợp lý 2[ (95 + 5^11 : 5^10) :2^2 +180] – 2^2 .10^2+2017^0
2[ (95 + 5^11 : 5^10) :2^2 +180] – 2^2 .10^2+2017^0 = 2[ ( 95 + 5 ) : 4 + 180 ] – 4 . 100 + 1 = 2[ 100 : 4 +180 ] – 400 + 1 = 2 . 205 – 400 + 1 = 410 – 400 + 1 = 11 Bình luận
2[ (95 + 5^11 : 5^10) :2^2 +180] – 2^2 .10^2+2017^0
= 2[ ( 95 + 5 ) : 4 + 180 ] – 4 . 100 + 1
= 2[ 100 : 4 +180 ] – 400 + 1
= 2 . 205 – 400 + 1
= 410 – 400 + 1
= 11