tính khối lượng mol của a,CuHso4 b,Cl2 c,Ag d,Ba(H2Po4)2 13/08/2021 Bởi Elliana tính khối lượng mol của a,CuHso4 b,Cl2 c,Ag d,Ba(H2Po4)2
a, MCu(HSO4)2=64+(1*2)+(32*2)+(16*8)=258 g/mol b, MCl2=35.5*2=71 g/mol c, MAg=108 g/mol d, MBa(H2PO4)2=137+(2*2)+(31*2)+(16*8)=331 g/mol Bình luận
Em tham khảo nha : \(\begin{array}{l}a)\\{M_{CuS{O_4}}} = {M_{Cu}} + {M_S} + 4{M_O} = 64 + 32 + 4 \times 16 = 160g/mol\\{M_{Cu{{(HS{O_4})}_2}}} = {M_{Cu}} + 2{M_H} + 2{M_S} + 8{M_O} = 64 + 2 + 2 \times 32 + 8 \times 16 = 258g/mol\\b)\\{M_{C{l_2}}} = 2{M_{Cl}} = 2 \times 35,5 = 71g/mol\\c)\\{M_{Ag}} = 108g/mol\\d)\\{M_{Ba{{({H_2}P{O_4})}_2}}} = {M_{Ba}} + 4{M_H} + 2{M_P} + 8{M_O} = 137 + 4 + 2 \times 31 + 8 \times 16 = 331g/mol\end{array}\) Bình luận
a, MCu(HSO4)2=64+(1*2)+(32*2)+(16*8)=258 g/mol
b, MCl2=35.5*2=71 g/mol
c, MAg=108 g/mol
d, MBa(H2PO4)2=137+(2*2)+(31*2)+(16*8)=331 g/mol
Em tham khảo nha :
\(\begin{array}{l}
a)\\
{M_{CuS{O_4}}} = {M_{Cu}} + {M_S} + 4{M_O} = 64 + 32 + 4 \times 16 = 160g/mol\\
{M_{Cu{{(HS{O_4})}_2}}} = {M_{Cu}} + 2{M_H} + 2{M_S} + 8{M_O} = 64 + 2 + 2 \times 32 + 8 \times 16 = 258g/mol\\
b)\\
{M_{C{l_2}}} = 2{M_{Cl}} = 2 \times 35,5 = 71g/mol\\
c)\\
{M_{Ag}} = 108g/mol\\
d)\\
{M_{Ba{{({H_2}P{O_4})}_2}}} = {M_{Ba}} + 4{M_H} + 2{M_P} + 8{M_O} = 137 + 4 + 2 \times 31 + 8 \times 16 = 331g/mol
\end{array}\)