Tính: (làm chi tiết nha) `\frac{\sqrt{6-\sqrt{11}}}{\sqrt{22}-\sqrt{2}}“+ 6/\sqrt{2}-“\frac{3}{\sqrt{2}+1}` 14/07/2021 Bởi Savannah Tính: (làm chi tiết nha) `\frac{\sqrt{6-\sqrt{11}}}{\sqrt{22}-\sqrt{2}}“+ 6/\sqrt{2}-“\frac{3}{\sqrt{2}+1}`
Đáp án: `\sqrt{6-sqrt{11}}/(sqrt{22}-sqrt2)+6/sqrt2-3/(sqrt2+1)` `=(\sqrt2.sqrt{6-sqrt{11}})/(sqrt2(sqrt{22}-sqrt2))+(3.2)/sqrt2-(3(sqrt2-1))/((sqrt2+1)(sqrt2-1))` `=(sqrt{12-2sqrt{11}})/(sqrt2(sqrt{22}-sqrt2))+3sqrt2-(3(sqrt2-1))` `=sqrt{11-2sqrt{11}+1}/(sqrt2.sqrt2(sqrt{11}-1))+3sqrt2-3sqrt2+3` `=sqrt{(sqrt{11}-1)^2}/(2(sqrt{11}-1))+3` `=(sqrt{11}-1)/(2(sqrt{11}-1))+3` `=1/2+3=7/2`. Bình luận
`(\sqrt{6}-\sqrt{11})/(\sqrt{22}-\sqrt{2})+6/\sqrt{2}-3/(\sqrt{2}+1)` `=(\sqrt{12}-2\sqrt{11})/(2\sqrt{11}-2)+(6\sqrt{2})/2-(3(\sqrt{2}-1))/(2-1)` `=(\sqrt{(\sqrt{11}-1)^2})/(2(\sqrt{11}-1))+3\sqrt{2}-3\sqrt{2}+3` `=(\sqrt{11}-1)/(2(\sqrt{11}-1))+3` `=1/2+3` `=7/2` Bình luận
Đáp án:
`\sqrt{6-sqrt{11}}/(sqrt{22}-sqrt2)+6/sqrt2-3/(sqrt2+1)`
`=(\sqrt2.sqrt{6-sqrt{11}})/(sqrt2(sqrt{22}-sqrt2))+(3.2)/sqrt2-(3(sqrt2-1))/((sqrt2+1)(sqrt2-1))`
`=(sqrt{12-2sqrt{11}})/(sqrt2(sqrt{22}-sqrt2))+3sqrt2-(3(sqrt2-1))`
`=sqrt{11-2sqrt{11}+1}/(sqrt2.sqrt2(sqrt{11}-1))+3sqrt2-3sqrt2+3`
`=sqrt{(sqrt{11}-1)^2}/(2(sqrt{11}-1))+3`
`=(sqrt{11}-1)/(2(sqrt{11}-1))+3`
`=1/2+3=7/2`.
`(\sqrt{6}-\sqrt{11})/(\sqrt{22}-\sqrt{2})+6/\sqrt{2}-3/(\sqrt{2}+1)`
`=(\sqrt{12}-2\sqrt{11})/(2\sqrt{11}-2)+(6\sqrt{2})/2-(3(\sqrt{2}-1))/(2-1)`
`=(\sqrt{(\sqrt{11}-1)^2})/(2(\sqrt{11}-1))+3\sqrt{2}-3\sqrt{2}+3`
`=(\sqrt{11}-1)/(2(\sqrt{11}-1))+3`
`=1/2+3`
`=7/2`