Tính: làm chi tiết $\sqrt{\sqrt{7+\sqrt{48}}}$`- 1/\sqrt{2}`

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1. `\root{2}{\root{2}{7+\root{2}{48}}}-1/(\root{2}{2})`

   `=\root{2}{\root{2}{(2+\root{2}{\3})^2})-1/(\root{2}{2})`

   `=\root{2}{(2+\root{2}{\3}))-1/(\root{2}{2})`

   `=(\root{2}{(4+2\root{2}{\3})))/(\root{2}{2})-1/(\root{2}{2})`

   `=(\root{2}{(4+2\root{2}{\3}))-1)/(\root{2}{2})`

   `=(\root{2}{(\root{2}{\3}+1)^2)-1)/(\root{2}{2})`

   `=(\root{2}{3}+1-1)/(\root{2}{2})`

   `=(\root{2}{3})/(\root{2}{2})`

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