Tính log1/2⁡2 + 2log1/2⁡1/3 + log1/2⁡3/8

Tính log1/2⁡2 + 2log1/2⁡1/3 + log1/2⁡3/8

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  1. Đáp án:log1/2⁡2 + 2log1/2⁡1/3 + log1/2⁡3/8== log1/2⁡1/12.

     

    Giải thích các bước giải:

     log1/2⁡2 + 2log1/2⁡1/3 + log1/2⁡3/8

    = log1/2⁡2 + log1/2⁡1/3 + log1/2⁡1/3 + log1/2⁡3/8

    = log1/2⁡(2.1/3.1/3 .3/8) = log1/2⁡1/12.

     

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  2.             log1/2⁡2 + 2log1/2⁡1/3 + log1/2⁡3/8

     GIẢI : log1/2⁡2 + 2log1/2⁡1/3 + log1/2⁡3/8

    = log1/2⁡2 + log1/2⁡1/3 + log1/2⁡1/3 + log1/2⁡3/8

    = log1/2⁡(2.1/3.1/3 .3/8) = log1/2⁡1/12.

     

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