tính nhanh, nếu có thể a, 6^7: 6^5+5^2.2^5 b, 36.2020-2020.26 c, 35.273+3^3 . 35 d,{2^3.40-[95-(8-3)^2]}:50 31/10/2021 Bởi Abigail tính nhanh, nếu có thể a, 6^7: 6^5+5^2.2^5 b, 36.2020-2020.26 c, 35.273+3^3 . 35 d,{2^3.40-[95-(8-3)^2]}:50
a, $6^{7}$ : $6^{5}$ +$5^{2}$ .$2^{5}$ = 36+800 =836 b, 36.2020-2020.26 =(36-26).2020 = 10.2020 = 20200 c, 35.273+$3^{3}$ . 35 =35.(273+$3^{3}$ ) =35. (273+27) = 35.300 =10500 d,{$2^{3}$ .40-[95-(8-3)²]}:50 ={8.40-[95-$5^{2}$ ]}:50 ={8.40-{95-25}:50 ={8.40-70}:50 ={320-70}:50 =250:50 =5 Bình luận
a, 6^7: 6^5+5^2.2^5= 36+800=836 b, 36.2020-2020.26=(36-26).2020 = 10.2020 = 20200 c, 35.273+3^3 . 35=35.(273+3^3)=35. (273+27) = 35.300 =10500 d,{2^3.40-[95-(8-3)^2]}:50={8.40-[95-5^2]}:50={8.40-{95-25}:50={8.40-70}:50={320-70}:50 =250:50 =5 Bình luận
a, $6^{7}$ : $6^{5}$ +$5^{2}$ .$2^{5}$
= 36+800
=836
b, 36.2020-2020.26
=(36-26).2020
= 10.2020
= 20200
c, 35.273+$3^{3}$ . 35
=35.(273+$3^{3}$ )
=35. (273+27)
= 35.300
=10500
d,{$2^{3}$ .40-[95-(8-3)²]}:50
={8.40-[95-$5^{2}$ ]}:50
={8.40-{95-25}:50
={8.40-70}:50
={320-70}:50
=250:50
=5
a, 6^7: 6^5+5^2.2^5= 36+800=836
b, 36.2020-2020.26=(36-26).2020 = 10.2020 = 20200
c, 35.273+3^3 . 35=35.(273+3^3)=35. (273+27) = 35.300 =10500
d,{2^3.40-[95-(8-3)^2]}:50={8.40-[95-5^2]}:50={8.40-{95-25}:50={8.40-70}:50={320-70}:50
=250:50
=5