tính PTK: PTK NaOH PTK CuSO4 PTK K2CO3 PTK Fe2(SO4)3 PTK CuO PTK Fe2O3 PTK A1(NO3)3 10/07/2021 Bởi Adeline tính PTK: PTK NaOH PTK CuSO4 PTK K2CO3 PTK Fe2(SO4)3 PTK CuO PTK Fe2O3 PTK A1(NO3)3
`PTK_(NaOH)=NTK_(Na)+NTK_(O)+NKT_(H)=23+16+1=40(đvC)``PTK_(CuSO_4)= NTK_(Cu)+ NTK_(S)+4*NTK_(O)= 64+32+16*4=160(đvC)``PTK_{K_2CO_3}=NTK_K+NTK_C+NTK_O=2*39+12+3*16=138(đvC)``PTK_(Fe_2(SO_4)_3)=NTK_(Fe)+3NTK_(SO_4)=56*2+32*3+16*12=400(đvC)``PTK_(CuO)=PTK_(CuO)=NTK_(Fe)+3NTK_(SO_4)=56*2+32*3+16*12=400(đvC)``PTK_(Fe_2O_3)=NTK_(Fe)+NTK_O=56*2+16*3=160(đvC)``PTK_(Al(NO_3)_3)=NTK_(Al)+3NTK_(NO_3)=27+3(14+4*16)=261(đvC)` Bình luận
PTK NaOH=23+16+1=40 PTK CuSO4=64+32+4.16=160 PTK K2CO3=2.39+12+3.16=138 PTK Fe2(SO4)3=2.56+3(32+4.16)=400 PTK CuO=64+16=80 PTK Fe2O3=2.56+3.16=160 PTK A1(NO3)3=27+3(14+4.16)=261 Bình luận
`PTK_(NaOH)=NTK_(Na)+NTK_(O)+NKT_(H)=23+16+1=40(đvC)`
`PTK_(CuSO_4)= NTK_(Cu)+ NTK_(S)+4*NTK_(O)= 64+32+16*4=160(đvC)`
`PTK_{K_2CO_3}=NTK_K+NTK_C+NTK_O=2*39+12+3*16=138(đvC)`
`PTK_(Fe_2(SO_4)_3)=NTK_(Fe)+3NTK_(SO_4)=56*2+32*3+16*12=400(đvC)`
`PTK_(CuO)=PTK_(CuO)=NTK_(Fe)+3NTK_(SO_4)=56*2+32*3+16*12=400(đvC)`
`PTK_(Fe_2O_3)=NTK_(Fe)+NTK_O=56*2+16*3=160(đvC)`
`PTK_(Al(NO_3)_3)=NTK_(Al)+3NTK_(NO_3)=27+3(14+4*16)=261(đvC)`
PTK NaOH=23+16+1=40
PTK CuSO4=64+32+4.16=160
PTK K2CO3=2.39+12+3.16=138
PTK Fe2(SO4)3=2.56+3(32+4.16)=400
PTK CuO=64+16=80
PTK Fe2O3=2.56+3.16=160
PTK A1(NO3)3=27+3(14+4.16)=261