Tính thể tích khí : 1)1gH2O 2)2gNO2 3)3gHCl 4)4gSO2 5)5gPH3 Giúp mình nhé 16/08/2021 Bởi Serenity Tính thể tích khí : 1)1gH2O 2)2gNO2 3)3gHCl 4)4gSO2 5)5gPH3 Giúp mình nhé
1) \({n_{{H_2}O}} = \frac{1}{{18}} \to {V_{{H_2}O}} = \frac{1}{{18}}.22,4 = 1,2444{\text{ lít}}\) 2) \({n_{N{O_2}}} = \frac{2}{{14 + 16.2}} = \frac{1}{{23}} \to {V_{N{O_2}}} = \frac{1}{{23}}.22,4 = 0,9739{\text{ lít}}\) 3) \({n_{HCl}} = \frac{3}{{36,5}} \to {V_{HCl}} = \frac{3}{{36,5}}.22,4 = 1,841{\text{ lít}}\) 4) \({n_{S{O_2}}} = \frac{4}{{32 + 16.2}} = \frac{1}{{16}}{\text{ mol}} \to {{\text{V}}_{S{O_2}}} = \frac{1}{{16}}.22,4 = 1,4{\text{ lít}}\) 5) \({n_{P{H_3}}} = \frac{5}{{31 + 1.3}} = \frac{5}{{34}} \to {V_{P{H_3}}} = \frac{5}{{34}}.22,4 = 3,294{\text{ lít}}\) Bình luận
1)
\({n_{{H_2}O}} = \frac{1}{{18}} \to {V_{{H_2}O}} = \frac{1}{{18}}.22,4 = 1,2444{\text{ lít}}\)
2)
\({n_{N{O_2}}} = \frac{2}{{14 + 16.2}} = \frac{1}{{23}} \to {V_{N{O_2}}} = \frac{1}{{23}}.22,4 = 0,9739{\text{ lít}}\)
3)
\({n_{HCl}} = \frac{3}{{36,5}} \to {V_{HCl}} = \frac{3}{{36,5}}.22,4 = 1,841{\text{ lít}}\)
4)
\({n_{S{O_2}}} = \frac{4}{{32 + 16.2}} = \frac{1}{{16}}{\text{ mol}} \to {{\text{V}}_{S{O_2}}} = \frac{1}{{16}}.22,4 = 1,4{\text{ lít}}\)
5)
\({n_{P{H_3}}} = \frac{5}{{31 + 1.3}} = \frac{5}{{34}} \to {V_{P{H_3}}} = \frac{5}{{34}}.22,4 = 3,294{\text{ lít}}\)
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