tính tổng S = 10. (1/2.12 + 1/12.22 + 1/22.32 + …+1/2002.2012 ) 27/08/2021 Bởi Peyton tính tổng S = 10. (1/2.12 + 1/12.22 + 1/22.32 + …+1/2002.2012 )
S = 10. (1/2.12 + 1/12.22 + 1/22.32 + …+1/2002.2012 ) = 10/2.12 + 10/12.22 + 10/22.32 + …+10/2002.2012 ) =1/2-1/12+1/12-1/22+1/22-1/32+…+1/2002-1/2012) =1/2-1/2012 =1006/2012-1/2012 =1005/2012 Bình luận
`S = 10. (1/(2.12) + 1/(12.22) + 1/(22.32) + …+1/(2002.2012) )` `S = 10/(2.12) + 10/(12.22) + 10/(22.32) + …+10/(2002.2012)` `S = 1/2 – 1/12 + 1/12-1/22+1/22-1/32+…..+1/2002-1/2012` `S = 1/2 – 1/2012` `S = 1006/2012 – 1/2012` `S = 1005/2012` (Chúc bạn học tốt) Bình luận
S = 10. (1/2.12 + 1/12.22 + 1/22.32 + …+1/2002.2012 )
= 10/2.12 + 10/12.22 + 10/22.32 + …+10/2002.2012 )
=1/2-1/12+1/12-1/22+1/22-1/32+…+1/2002-1/2012)
=1/2-1/2012
=1006/2012-1/2012
=1005/2012
`S = 10. (1/(2.12) + 1/(12.22) + 1/(22.32) + …+1/(2002.2012) )`
`S = 10/(2.12) + 10/(12.22) + 10/(22.32) + …+10/(2002.2012)`
`S = 1/2 – 1/12 + 1/12-1/22+1/22-1/32+…..+1/2002-1/2012`
`S = 1/2 – 1/2012`
`S = 1006/2012 – 1/2012`
`S = 1005/2012`
(Chúc bạn học tốt)