Viết các đồng phân mạch hở và gọi tên của: C4H10, C5H12, C4H8, C5H10, C5H8

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1. Em tham khảo nha:

   \(\begin{array}{l}
   {C_4}{H_{10}}:\\
   C{H_3} – C{H_2} – C{H_2} – C{H_3}:bu\tan \\
   C{H_3} – CH(C{H_3}) – C{H_3}:2 – metylpropan\\
   {C_5}{H_{12}}:\\
   C{H_3} – C{H_2} – C{H_2} – C{H_2} – C{H_3}:pen\tan \\
   C{H_3} – CH(C{H_3}) – C{H_2} – C{H_3}:2 – metyl\,bu\tan \\
   C{H_3} – C{(C{H_3})_2} – C{H_3}:2,2 – \dim etylpropan\\
   {C_4}{H_8}:\\
   C{H_2} = CH – C{H_2} – C{H_3}:but – 1 – en\\
   C{H_2} = C(C{H_3}) – C{H_3}:2 – metyl\,propen\\
   C{H_3} – CH = CH – C{H_3}:but – 2 – en\\
   {C_5}{H_{10}}:\\
   C{H_2} = CH – C{H_2} – C{H_2} – C{H_3}:pent – 1 – en\\
   C{H_2} = C(C{H_3}) – C{H_2} – C{H_3}:2 – metyl\,but – 1 – en\\
   C{H_2} = CH – CH(C{H_3}) – C{H_3}:3 – metylbut – 1 – en\\
   C{H_3} – CH = CH – C{H_2} – C{H_3}:pent – 2 – en\\
   C{H_3} – CH(C{H_3}) = CH – C{H_3}:2 – metyl\,but – 2 – en\\
   {C_5}{H_8}:\\
   CH \equiv C – C{H_2} – C{H_2} – C{H_3}:pent – 1 – in\\
   CH \equiv C – CH(C{H_3}) – C{H_3}:3 – metyl\,but – 1 – in\\
   C{H_3} – C \equiv C – C{H_2} – C{H_3}:pent – 2 – in
   \end{array}\)

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