Viết chuỗi phương trình $Al$ → $Al_{2}O_{3}$ → $AlCl_{3}$ → $Al(NO_{3})_{3}$ → $Al(OH)_{3}$ 19/08/2021 Bởi Clara Viết chuỗi phương trình $Al$ → $Al_{2}O_{3}$ → $AlCl_{3}$ → $Al(NO_{3})_{3}$ → $Al(OH)_{3}$
\[\begin{array}{l}4Al + 3{O_2} \to 2A{l_2}{O_3}({t^0})\\A{l_2}{O_3} + 6HCl \to 2AlC{l_3} + 3{H_2}O\\AlC{l_3} + 3AgN{O_3} \to Al{(N{O_3})_3} + 3AgCl\\Al{(N{O_3})_3} + 3NaOH \to Al{(OH)_3} + 3NaN{O_3}({t^0})\end{array}\] Bình luận
$4Al+3O_2\buildrel{{t^o}}\over\to 2Al_2O_3$ $Al_2O_3+6HCl\to 2AlCl_3+3H_2O$ $AlCl_3+3AgNO_3\to 3AgCl+Al(NO_3)_3$ $Al(NO_3)_3+3NaOH\to 3NaNO_3+Al(OH)_3$ Bình luận
\[\begin{array}{l}
4Al + 3{O_2} \to 2A{l_2}{O_3}({t^0})\\
A{l_2}{O_3} + 6HCl \to 2AlC{l_3} + 3{H_2}O\\
AlC{l_3} + 3AgN{O_3} \to Al{(N{O_3})_3} + 3AgCl\\
Al{(N{O_3})_3} + 3NaOH \to Al{(OH)_3} + 3NaN{O_3}({t^0})
\end{array}\]
$4Al+3O_2\buildrel{{t^o}}\over\to 2Al_2O_3$
$Al_2O_3+6HCl\to 2AlCl_3+3H_2O$
$AlCl_3+3AgNO_3\to 3AgCl+Al(NO_3)_3$
$Al(NO_3)_3+3NaOH\to 3NaNO_3+Al(OH)_3$