Viết CTCTcacs đồng phân (cấu tạo)anken ứng với CTPT là C4H8 và C5H10 gọi tên thay thế 19/11/2021 Bởi Maya Viết CTCTcacs đồng phân (cấu tạo)anken ứng với CTPT là C4H8 và C5H10 gọi tên thay thế
\(\begin{array}{l}*{C_4}{H_8}:\\C{H_2} = CH – C{H_2} – C{H_3}:but – 1 – en\\C{H_3} – CH = CH – C{H_3}:but – 2 – en\\C{H_2} = C(C{H_3}) – C{H_3}:2metylpropen\\*{C_5}{H_{10}}\\C{H_2} = CH – C{H_2} – C{H_2} – C{H_3}:pent – 1 – en\\C{H_3} – CH = CH – C{H_2} – C{H_3}:pent – 2 – en\\C{H_2} = C(C{H_3}) – C{H_2} – C{H_3}:2 – metylbut – 1 – en\\C{H_2} = CH – CH(C{H_3}) – C{H_3}:3metylbut – 1 – en\\C{H_3} – C(C{H_3}) = CH – C{H_3}:2metylbut – 2 – en\end{array}\) Bình luận
\(\begin{array}{l}
*{C_4}{H_8}:\\
C{H_2} = CH – C{H_2} – C{H_3}:but – 1 – en\\
C{H_3} – CH = CH – C{H_3}:but – 2 – en\\
C{H_2} = C(C{H_3}) – C{H_3}:2metylpropen\\
*{C_5}{H_{10}}\\
C{H_2} = CH – C{H_2} – C{H_2} – C{H_3}:pent – 1 – en\\
C{H_3} – CH = CH – C{H_2} – C{H_3}:pent – 2 – en\\
C{H_2} = C(C{H_3}) – C{H_2} – C{H_3}:2 – metylbut – 1 – en\\
C{H_2} = CH – CH(C{H_3}) – C{H_3}:3metylbut – 1 – en\\
C{H_3} – C(C{H_3}) = CH – C{H_3}:2metylbut – 2 – en
\end{array}\)