Viết đồng phân cấu tạo mạch hở của C4H8O2,C3H8O2,C4H10O

Bởi

Viết đồng phân cấu tạo mạch hở của C4H8O2,C3H8O2,C4H10O

0 bình luận về “Viết đồng phân cấu tạo mạch hở của C4H8O2,C3H8O2,C4H10O”

  2. + \(C_4H_8O_2\):

    \(C{H_3}C{H_2}C{H_2}COOH;C{H_3}C{H_2}COOC{H_3};C{H_3}COOC{H_2}C{H_3}\)

    \(HCOOC{H_2}C{H_2}C{H_3};HCOOCH{(C{H_3})_2}\)

    \(C{H_2} = CH – CHOH – C{H_2}OH;C{H_2}OH – CH = CH – C{H_2}OH\)

    \(C{H_2}OH – C{H_2} – O – CH = C{H_2};C{H_2}OH – CH = CH – O – C{H_3}\)

    \(C{H_2}OH – C{H_2} – C{H_2} – CHO;C{H_3} – CHOH – C{H_2} – CHO;C{H_3} – C{H_2} – CHOH – CHO\)

    \(C{H_2}OH – CH(C{H_3}) – CHO;C{H_3} – COH(C{H_3}) – CHO\)

    \(C{H_3} – O – C{H_2} – C{H_2} – CHO;C{H_3} – O – CH(C{H_3}) – CHO\)

    \(C{H_3} – C{H_2} – O – C{H_2} – CHO\)

    \(C{H_2}OH – CO – C{H_2} – C{H_3};C{H_3} – CO – CHOH – C{H_3};C{H_3} – CO – C{H_2} – C{H_2}OH\)

    \(C{H_3} – CO – C{H_2} – CO – C{H_3}\)

    +\(C_3H_8O_2\)

    \(C{H_2}OH – CHOH – C{H_3};C{H_2}OH – C{H_2} – C{H_2}OH\)

    \(C{H_3} – O – C{H_2} – C{H_2}OH\)

    +\(C_4H_{10}O\)

    \(C{H_2}OH – C{H_2} – C{H_2} – C{H_3};C{H_3} – CHOH – C{H_2} – C{H_3}\)

    \(C{H_2}OH – CH(C{H_3}) – C{H_3};C{H_3} – COH(C{H_3}) – C{H_3}\)

    \(C{H_3} – O – C{H_2} – C{H_2} – C{H_3};C{H_3} – C{H_2} – O – C{H_2} – C{H_3}\)

    \(C{H_3} – CH(C{H_3}) – O – C{H_3}\)

    Bình luận

Viết một bình luận