viét dưới dạng tích a 4x^4 – 121 b / 27- 8x mũ 3 c 1+125 mũ 3 d16y mũ2 – 160 21/08/2021 Bởi Ruby viét dưới dạng tích a 4x^4 – 121 b / 27- 8x mũ 3 c 1+125 mũ 3 d16y mũ2 – 160
Đáp án: a, $4x^{4}$ – 121 = (2x²)² – 11² = (2x² – 11)(2x² + 11) b, 27 – 8x³ = 3³ – (2x)³ = (3 – 2x)(9 – 6x + 4x² ) c, 1+125³ = ( 1+ 125)( 1 + 125+ 125²) d, 16y² – 160 = (4y)² – (4$\sqrt{10}$ )² = (4y – 4$\sqrt{10}$ ) ( 4y + 4$\sqrt{10}$ ) Bình luận
`a) 4x^4 – 121=(2x^2)^2-11^2=(2x^2-11)(2x^2+11)` `b ) 27- 8x ^ 3=3^3-(2x)^3=(3-2x)(9+6x+4x^2)` `c) 1+125 ^ 3=(1+125)(1-125+125^2)` `d)16y^2 – 16=(4y)^2-4^2=(4y-4)(4y+4)` Bình luận
Đáp án:
a, $4x^{4}$ – 121
= (2x²)² – 11²
= (2x² – 11)(2x² + 11)
b, 27 – 8x³
= 3³ – (2x)³
= (3 – 2x)(9 – 6x + 4x² )
c, 1+125³
= ( 1+ 125)( 1 + 125+ 125²)
d, 16y² – 160
= (4y)² – (4$\sqrt{10}$ )²
= (4y – 4$\sqrt{10}$ ) ( 4y + 4$\sqrt{10}$ )
`a) 4x^4 – 121=(2x^2)^2-11^2=(2x^2-11)(2x^2+11)`
`b ) 27- 8x ^ 3=3^3-(2x)^3=(3-2x)(9+6x+4x^2)`
`c) 1+125 ^ 3=(1+125)(1-125+125^2)`
`d)16y^2 – 16=(4y)^2-4^2=(4y-4)(4y+4)`