Hóa học viết phương trình hóa học theo sơ đồ sau: Al4C3->CH4->C2H2->C6H6->C6H5Br 13/07/2021 By Arya viết phương trình hóa học theo sơ đồ sau: Al4C3->CH4->C2H2->C6H6->C6H5Br
`Al_4C_3+12H_2O->4Al(OH)_3+3CH_4` $2CH_4\xrightarrow[\text{Làm lạnh nhanh}]{1500^oC}C_2H_2+3H_2$ $3CH\equiv CH\xrightarrow{t^o,xt,P}C_6H_6$ $C_6H_6+Br_2\xrightarrow[Fe]{t^o}C_6H_5Br+HBr$ Trả lời
$Al_4C_3+12H_2O\to 3CH_4+4Al(OH)_3$ $2CH_4\xrightarrow{{1500^oC}} C_2H_2+3H_2$ $3C_2H_2\xrightarrow{{600^oC, C}} C_6H_6$ $C_6H_6+Br_2\xrightarrow{{Fe, t^o}} C_6H_5Br+HBr$ Trả lời
`Al_4C_3+12H_2O->4Al(OH)_3+3CH_4`
$2CH_4\xrightarrow[\text{Làm lạnh nhanh}]{1500^oC}C_2H_2+3H_2$
$3CH\equiv CH\xrightarrow{t^o,xt,P}C_6H_6$
$C_6H_6+Br_2\xrightarrow[Fe]{t^o}C_6H_5Br+HBr$
$Al_4C_3+12H_2O\to 3CH_4+4Al(OH)_3$
$2CH_4\xrightarrow{{1500^oC}} C_2H_2+3H_2$
$3C_2H_2\xrightarrow{{600^oC, C}} C_6H_6$
$C_6H_6+Br_2\xrightarrow{{Fe, t^o}} C_6H_5Br+HBr$