viết phương trình phản ứng: propan → etilen →etan → etyl clorua →etilen →etylen glicol 10/08/2021 Bởi Katherine viết phương trình phản ứng: propan → etilen →etan → etyl clorua →etilen →etylen glicol
$CH_3-CH_2-CH_3 \buildrel{{t^o, xt}}\over\longrightarrow CH_4+CH_2=CH_2$ $CH_2=CH_2+ H_2\buildrel{{Ni, t^o}}\over\longrightarrow CH_3-CH_3$ $CH_3-CH_3+Cl_2\buildrel{{as}}\over\to C_2H_5Cl+HCl$ $C_2H_5Cl+KOH\buildrel{{C_2H_5OH, t^o}}\over\longrightarrow C_2H_4+KCl+H_2O$ $3C_2H_4+2KMnO_4+4H_2O\to 3 CH_2OHCH_2OH + 2MnO_2+2KOH$ Bình luận
`C_3H_8->C_2H_4+CH_4` `C_2H_4+H_2\overset(t^0,Ni)toC_2H_6` `C_2H_6+Cl_2\overset(askt)toC_2H_5Cl+HCl` `C_2H_5Cl->C_2H_4+HCl` `3C_2H_4+2KMnO_4+4H_2O\overset(t^0,Ni)to2MnO_2+2KOH+3C_2H_4(OH)_2` Bình luận
$CH_3-CH_2-CH_3 \buildrel{{t^o, xt}}\over\longrightarrow CH_4+CH_2=CH_2$
$CH_2=CH_2+ H_2\buildrel{{Ni, t^o}}\over\longrightarrow CH_3-CH_3$
$CH_3-CH_3+Cl_2\buildrel{{as}}\over\to C_2H_5Cl+HCl$
$C_2H_5Cl+KOH\buildrel{{C_2H_5OH, t^o}}\over\longrightarrow C_2H_4+KCl+H_2O$
$3C_2H_4+2KMnO_4+4H_2O\to 3 CH_2OHCH_2OH + 2MnO_2+2KOH$
`C_3H_8->C_2H_4+CH_4`
`C_2H_4+H_2\overset(t^0,Ni)toC_2H_6`
`C_2H_6+Cl_2\overset(askt)toC_2H_5Cl+HCl`
`C_2H_5Cl->C_2H_4+HCl` `3C_2H_4+2KMnO_4+4H_2O\overset(t^0,Ni)to2MnO_2+2KOH+3C_2H_4(OH)_2`