Viết pthh hoàn thành chuỗi FeS2 -> SO2 -> Fe2O3 -> Na2SO4 -> NaCl 05/11/2021 Bởi Cora Viết pthh hoàn thành chuỗi FeS2 -> SO2 -> Fe2O3 -> Na2SO4 -> NaCl
Đáp án: \(\begin{array}{l}\begin{array}{*{20}{l}}{4Fe{S_2}}& + &{11{O_2}}& \to &{2F{e_2}{O_3}}& + &{8S{O_2}}\end{array}\\F{e_2}{O_3}\; + \;6NaHS{O_4}\; \to F{e_2}{\left( {S{O_4}} \right)_3}\; + \;3N{a_2}S{O_4}\; + \;3{H_2}O\\N{a_2}S{O_4} + BaC{l_2} \to BaS{O_4} + 2NaCl\end{array}\) Bình luận
$4FeS_{2}$ + $11O_{2}$ → $2Fe_{2}O_{3}$ + $8SO_{2}$ $2SO_{2}$ + $O_{2}$ $⇄^{V_2O_5,450^o}$ $2SO_{3}$ $SO_{3}$ + $H_{2}O$ → $H_{2}SO_{4}$ CuO + $H_{2}SO_{4}$ → $CuSO_{4}$ + $H_{2}O$ $CuSO_{4}$ + 2NaOH → $Cu(OH)_{2}$ + $Na_{2}SO_{4}$ $Na_{2}SO_{4}$ + $Ba(OH)_{2}$ → $BaSO_{4}$ + 2NaOH Zn + 2NaOH → $Na_{2}ZnO_{2}$ + $H_{2}$ Bình luận
Đáp án:
\(\begin{array}{l}
\begin{array}{*{20}{l}}
{4Fe{S_2}}& + &{11{O_2}}& \to &{2F{e_2}{O_3}}& + &{8S{O_2}}
\end{array}\\
F{e_2}{O_3}\; + \;6NaHS{O_4}\; \to F{e_2}{\left( {S{O_4}} \right)_3}\; + \;3N{a_2}S{O_4}\; + \;3{H_2}O\\
N{a_2}S{O_4} + BaC{l_2} \to BaS{O_4} + 2NaCl
\end{array}\)
$4FeS_{2}$ + $11O_{2}$ → $2Fe_{2}O_{3}$ + $8SO_{2}$
$2SO_{2}$ + $O_{2}$ $⇄^{V_2O_5,450^o}$ $2SO_{3}$
$SO_{3}$ + $H_{2}O$ → $H_{2}SO_{4}$
CuO + $H_{2}SO_{4}$ → $CuSO_{4}$ + $H_{2}O$
$CuSO_{4}$ + 2NaOH → $Cu(OH)_{2}$ + $Na_{2}SO_{4}$
$Na_{2}SO_{4}$ + $Ba(OH)_{2}$ → $BaSO_{4}$ + 2NaOH
Zn + 2NaOH → $Na_{2}ZnO_{2}$ + $H_{2}$