Viết PTHH Theo sơ đồ chuyển hóa sau: 1. C2H4–>C2H5OH–>CH3COOH–>(CH3COO)2Zn 2. Glucozơ–> rượu etylic–>axit Axetic–> natri axetat 3. C4H10–>CH3CO

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1. Đáp án:

    

   Giải thích các bước giải:

   $1/$

   $C_2H_4 + H_2O \xrightarrow{t^o,H^+} C_2H_5OH$

   $C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O$

   $2CH_3COOH + Zn → (CH_3COO)_2Zn + H_2$

   $2/$

   $C_6H_{12}O_6 \xrightarrow{t^o,men\ rượu} 2CO_2 + 2C_2H_5OH$

   $C_2H_5OH + O_2 \xrightarrow{men\ giấm} CH_3COOH + H_2O$

   $CH_3COOH + NaOH → CH_3COONa + H_2O$
   $3/$

   $C_4H_{10} +2,5 O_2 \xrightarrow{t^o,xt} 2CH_3COOH + H_2O$

   $CH_3COOH + C_2H_5OH \buildrel{{H^+}}\over\rightleftharpoons CH_3COOC_2H_5 + H_2O$

   $CH_3COOC_2H_5 + NaOH → CH_3COONa + C_2H_5OH$

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2. 1.

   C2H4+H2O⇒C2H5OH

   C2H5OH+O2⇒CH3COOH+H2O

   2CH3COOH+Zn⇒H2↑+(CH3COO)2Zn

   2.

   C6H12O6⇒2C2H5OH+2CO2↑

   C2H5OH+O2⇒CH3COOH+H2O

   2CH3COOH+Na2CO3⇒2CH3COONa+H2O+CO2↑

   3.

   5O2+2C4H10⇒4CH3COOH+2H2O

   CH3COOH+C2H5OH⇄H2O+CH3COOC2H5

   NaOH+CH3COOC2H5⇒C2H5OH+CH3COONa

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