viết pthh theo sơ đồ sau:
a) butan->etilen->etan->etilen->etylclorua->ancol etylic->buta-1,3-dien->cao su buna
b) butan-> buta-1,3-dien-> butan-> etilen-> PE-> cacbonic
em cần gấp lắm ạ, cám ơn mn
viết pthh theo sơ đồ sau: a) butan->etilen->etan->etilen->etylclorua->ancol etylic->buta-1,3-dien->cao su buna b) butan-> buta-1,3-dien-> butan-> eti
By Isabelle
a)
\({C_4}{H_{10}}\xrightarrow{{{t^o}}}{C_2}{H_4} + {C_2}{H_6}\)
\({C_2}{H_4} + {H_2}\xrightarrow{{Ni,{t^o}}}{C_2}{H_6}\)
\({C_2}{H_6}\xrightarrow{{{t^o},xt}}{C_2}{H_4} + {H_2}\)
\({C_2}{H_4} + HCl\xrightarrow{{}}{C_2}{H_5}Cl\)
\({C_2}{H_5}Cl + NaOH\xrightarrow{{}}{C_2}{H_5}OH + NaCl\)
\(2{C_2}{H_5}OH\xrightarrow{{{t^o},xt}}C{H_2} = CH – CH = C{H_2} + 2{H_2}O + {H_2}\)
\(nC{H_2} = CH – CH = C{H_2}\xrightarrow{{{t^o},xt}}{( – C{H_2} – CH = CH – C{H_2} – )_n}\)
b)
\({C_4}{H_{10}}\xrightarrow{{{t^o},xt}}C{H_2} = CH – CH = C{H_2} + 2{H_2}\)
\(C{H_2} = CH – CH = C{H_2} + 2{H_2}\xrightarrow{{Ni,{t^o}}}C{H_3} – C{H_2} – C{H_2} – C{H_3}\)
\({C_4}{H_{10}}\xrightarrow{{{t^o}}}{C_2}{H_4} + {C_2}{H_6}\)
\(n{C_2}{H_4}\xrightarrow{{{t^o},xt}}{( – C{H_2} – C{H_2})_n}\)
\({( – C{H_2} – C{H_2})_n} + 3n{O_2}\xrightarrow{{{t^o}}}2nC{O_2} + 2n{H_2}O\)