Viết ptpu: 1. Natriaxetat -> Metan -> Metyl clorua -> Metylenclorua -> Clorofom -> Cacbon tetraclorua 2. Nhôm cacbua -> Metan -> Clometan -> điclometa

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1. Giải thích các bước giải:

   `1.` Dãy thứ nhất :

   $CH_3COONa+NaOH\xrightarrow{t^o,CaO}Na_2CO_3+CH_4↑$

   $CH_4+Cl_2\xrightarrow{As}CH_3Cl+HCl$

   $CH_3Cl+Cl_2\xrightarrow{As}CH_2Cl_2+HCl$

   $CH_2Cl_2+Cl_2\xrightarrow{As}CHCl_3+HCl$

   $CHCl_3+Cl_2\xrightarrow{As}CCl_4+HCl$

   `2.` Dãy thứ hai :

   `Al_4C_3+13H_2O→4Al(OH)_3↓+3CH_4↑`

   $CH_4+Cl_2\xrightarrow{As}CH_3Cl+HCl$

   $CH_3Cl+Cl_2\xrightarrow{As}CH_2Cl_2+HCl$

   $CH_2Cl_2+Cl_2\xrightarrow{As}CHCl_3+HCl$

   $CHCl_3+Cl_2\xrightarrow{As}CCl_4+HCl$

    

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2. 1.

   $CH_3COONa+NaOH\buildrel{{CaO, t^o}}\over\longrightarrow CH_4+Na_2CO_3$

   $CH_4+Cl_2\buildrel{{as}}\over\longrightarrow CH_3Cl+HCl$

   $CH_3Cl+Cl_2\buildrel{{as}}\over\longrightarrow CH_2Cl_2+HCl$

   $CH_2Cl_2+Cl_2\buildrel{{as}}\over\longrightarrow CHCl_3+ HCl$ 

   $CHCl_3+Cl_2\buildrel{{as}}\over\longrightarrow CCl_4+HCl$

   2.

   $Al_4C_3+12H_2O\rightarrow 3CH_4+4Al(OH)_3$

   $CH_4+Cl_2\buildrel{{as}}\over\longrightarrow CH_3Cl+HCl$

   $CH_3Cl+Cl_2\buildrel{{as}}\over\longrightarrow CH_2Cl_2+HCl$

   $CH_2Cl_2+Cl_2\buildrel{{as}}\over\longrightarrow CHCl_3+ HCl$ 

   $CHCl_3+Cl_2\buildrel{{as}}\over\longrightarrow CCl_4+HCl$

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