Viết ptpu của HO-C6H4-CH2OH tác dụng với Na,HCl,NaOH,dd Br2,CuO(t đô) 11/10/2021 Bởi Eloise Viết ptpu của HO-C6H4-CH2OH tác dụng với Na,HCl,NaOH,dd Br2,CuO(t đô)
$HO-C_6H_4-CH_2OH+2Na\to NaO-C_6H_4-CH_2ONa + H_2$ $HO-C_6H_4-CH_2OH+ HCl \to OH-C_6H_4-CH_2Cl+ H_2O$ $HO-C_6H_4-CH_2OH + NaOH \to NaO-C_6H_4-CH_2OH + H_2O$ $HO-C_6H_4-CH_2OH + 2Br_2\to HO-C_6H_2Br_2-CH_2OH + 2HBr$ $HO-C_6H_4-CH_2OH + CuO \buildrel{{t^o}}\over\to HO-C_6H_4-CHO+Cu+ H_2O$ Bình luận
$HO-C_6H_4-CH_2OH+2Na\to NaO-C_6H_4-CH_2ONa + H_2$
$HO-C_6H_4-CH_2OH+ HCl \to OH-C_6H_4-CH_2Cl+ H_2O$
$HO-C_6H_4-CH_2OH + NaOH \to NaO-C_6H_4-CH_2OH + H_2O$
$HO-C_6H_4-CH_2OH + 2Br_2\to HO-C_6H_2Br_2-CH_2OH + 2HBr$
$HO-C_6H_4-CH_2OH + CuO \buildrel{{t^o}}\over\to HO-C_6H_4-CHO+Cu+ H_2O$