Y= x^5/5 – 1/5x^3 + 1/2x^2 + 3/x – √x – sinx 22/08/2021 Bởi Iris Y= x^5/5 – 1/5x^3 + 1/2x^2 + 3/x – √x – sinx
Đáp án: `y= (x^5)/5 -1/5 x³ +1/2 x² +3/x -\sqrt{x} -sin x` `=>y’ = 5 . (x⁴)/5 – 3. 1/5 x² + 2. 1/2 x – 3/(x²) – \frac{1}{2\sqrt{x}} -cosx` `=> y’ = x⁴ – 3/5 x² +x -3/(x²) -\frac{1}{2\sqrt{x}}-cosx` Bình luận
Đáp án:
`y= (x^5)/5 -1/5 x³ +1/2 x² +3/x -\sqrt{x} -sin x`
`=>y’ = 5 . (x⁴)/5 – 3. 1/5 x² + 2. 1/2 x – 3/(x²) – \frac{1}{2\sqrt{x}} -cosx`
`=> y’ = x⁴ – 3/5 x² +x -3/(x²) -\frac{1}{2\sqrt{x}}-cosx`