Toán (2x+1) ² – (x-1) ² ; 9(x+5) ² – (x-7) ; 49(y-4) ² -9 (y+2) ² 12/09/2021 By Reese (2x+1) ² – (x-1) ² ; 9(x+5) ² – (x-7) ; 49(y-4) ² -9 (y+2) ²
Đáp án: $\begin{array}{l} a){\left( {2x + 1} \right)^2} – {\left( {x – 1} \right)^2}\\ = \left( {2x + 1 – x + 1} \right)\left( {2x + 1 + x – 1} \right)\\ = 3x.\left( {x + 2} \right)\\ b)kiem\,tra\,lai\,de\,nhe\\ c)\,49{\left( {y – 4} \right)^2} – 9{\left( {y + 2} \right)^2}\\ = {\left[ {7\left( {y – 4} \right)} \right]^2} – {\left[ {3\left( {y + 2} \right)} \right]^2}\\ = {\left( {7y – 28} \right)^2} – {\left( {3y + 6} \right)^2}\\ = \left( {7y – 28 – 3y – 6} \right)\left( {7y – 28 + 3y + 6} \right)\\ = \left( {4y – 34} \right)\left( {10y – 22} \right) \end{array}$ Trả lời
Đáp án:
$\begin{array}{l}
a){\left( {2x + 1} \right)^2} – {\left( {x – 1} \right)^2}\\
= \left( {2x + 1 – x + 1} \right)\left( {2x + 1 + x – 1} \right)\\
= 3x.\left( {x + 2} \right)\\
b)kiem\,tra\,lai\,de\,nhe\\
c)\,49{\left( {y – 4} \right)^2} – 9{\left( {y + 2} \right)^2}\\
= {\left[ {7\left( {y – 4} \right)} \right]^2} – {\left[ {3\left( {y + 2} \right)} \right]^2}\\
= {\left( {7y – 28} \right)^2} – {\left( {3y + 6} \right)^2}\\
= \left( {7y – 28 – 3y – 6} \right)\left( {7y – 28 + 3y + 6} \right)\\
= \left( {4y – 34} \right)\left( {10y – 22} \right)
\end{array}$