Toán (2x+1/3)-5/2=8/2 dau () la gia tri tuyet doi 06/09/2021 By Iris (2x+1/3)-5/2=8/2 dau () la gia tri tuyet doi
Đáp án: \(x = \frac{{37}}{{12}}\) hoặc \(x = \frac{{ – 41}}{{12}}\) Giải thích các bước giải: \[\begin{array}{l}\left| {2x + \frac{1}{3}} \right| – \frac{5}{2} = \frac{8}{2}\\ \Rightarrow \left| {2x + \frac{1}{3}} \right| = \frac{8}{2} + \frac{5}{2}\\ \Rightarrow \left| {2x + \frac{1}{3}} \right| = \frac{{13}}{2}\\TH1:\,2x + \frac{1}{3} = \frac{{13}}{2}\\2x = \frac{{13}}{2} – \frac{1}{3}\\2x = \frac{{37}}{6}\\x = \frac{{37}}{{12}}\\TH2:2x + \frac{1}{3} = – \frac{{13}}{2}\\2x = – \frac{{13}}{2} – \frac{1}{3}\\2x = \frac{{ – 41}}{6}\\x = \frac{{ – 41}}{{12}}\end{array}\] Trả lời
Đáp án:
\(x = \frac{{37}}{{12}}\) hoặc \(x = \frac{{ – 41}}{{12}}\)
Giải thích các bước giải:
\[\begin{array}{l}
\left| {2x + \frac{1}{3}} \right| – \frac{5}{2} = \frac{8}{2}\\
\Rightarrow \left| {2x + \frac{1}{3}} \right| = \frac{8}{2} + \frac{5}{2}\\
\Rightarrow \left| {2x + \frac{1}{3}} \right| = \frac{{13}}{2}\\
TH1:\,2x + \frac{1}{3} = \frac{{13}}{2}\\
2x = \frac{{13}}{2} – \frac{1}{3}\\
2x = \frac{{37}}{6}\\
x = \frac{{37}}{{12}}\\
TH2:2x + \frac{1}{3} = – \frac{{13}}{2}\\
2x = – \frac{{13}}{2} – \frac{1}{3}\\
2x = \frac{{ – 41}}{6}\\
x = \frac{{ – 41}}{{12}}
\end{array}\]
Đáp án:
Giải thích các bước giải:
|2x+1/3|-5/2=8/2
<=>2x=8/2+5/2-1/3
<=>2x=37/6
<=>x=37/12