$\dfrac{x-2}{4}=\dfrac{5+x}{3}$ $\to\dfrac{3(x-2)}{12}=\dfrac{4(5+x)}{12}$ $\to\dfrac{3x-6}{12}=\dfrac{20+4x}{12}$ $\to\dfrac{3x-6}{12}-\dfrac{20+4x}{12}=0$ $\to\dfrac{3x-6-20-4x}{12}=0$ $\to\dfrac{-x-26}{12}=0$ $\to-x-26=0$ $\to-x=26$ $\to x=-26$ Vậy $x=-26$. Bình luận
`(x – 2)/4 = (5 + x)/3` `⇔ 3(x-2)=4(5+x)` `⇔ 3x – 6 = 20 + 4x` `⇔ -6 – 20 = 4x – 3x` `⇔ -26 = x` $\text{Vậy x = -26}$ Bình luận
$\dfrac{x-2}{4}=\dfrac{5+x}{3}$
$\to\dfrac{3(x-2)}{12}=\dfrac{4(5+x)}{12}$
$\to\dfrac{3x-6}{12}=\dfrac{20+4x}{12}$
$\to\dfrac{3x-6}{12}-\dfrac{20+4x}{12}=0$
$\to\dfrac{3x-6-20-4x}{12}=0$
$\to\dfrac{-x-26}{12}=0$
$\to-x-26=0$
$\to-x=26$
$\to x=-26$
Vậy $x=-26$.
`(x – 2)/4 = (5 + x)/3`
`⇔ 3(x-2)=4(5+x)`
`⇔ 3x – 6 = 20 + 4x`
`⇔ -6 – 20 = 4x – 3x`
`⇔ -26 = x`
$\text{Vậy x = -26}$