4( 18- 5x) – 12( 3x – 7) = 15( 2x – 16) – 6(x+ 14)
(2x +2)(x – 1) – (x + 2).(2x + 1) = 0
4( 18- 5x) – 12( 3x – 7) = 15( 2x – 16) – 6(x+ 14) (2x +2)(x – 1) – (x + 2).(2x + 1) = 0
By Samantha
By Samantha
4( 18- 5x) – 12( 3x – 7) = 15( 2x – 16) – 6(x+ 14)
(2x +2)(x – 1) – (x + 2).(2x + 1) = 0
`4(18-5x)-12(3x-7) = 15(2x-16) – 6(x+14)`
`⇔ -56x + 156 = 24x – 324`
`⇔ -56x = 24x – 480`
`⇔ -80x = -480`
`⇔ x = 6`
Vậy `S = {6}`
`(2x+2)(x-1)-(x+2)(2x+1)=0`
`⇔ 2x^2 – 2 – 2x^2 – 5x – 2 = 0`
`⇔ -5x – 4 = 0`
`⇔ -5x = 4`
`⇔ x = -4/5`
Vậy `S = {-4/5}`
`4( 18- 5x) – 12( 3x – 7) = 15( 2x – 16) – 6(x+ 14)`
`<=> 72-20x-36x+84=30x-240-6x-84`
`<=>156-56x=24x-324`
`<=>80x=480`
`<=>x=6`
vậy nghiệm của pt `x=6`
`(2x +2)(x – 1) – (x + 2)(2x + 1) = 0`
`<=>2x²-2x+2x-2-2x²-x-4x-2=0`
`<=>-5x-4=0`
`<=>-5x=4`
`<=>x=-4/5`
vậy nghiệm của pt `x=-4/5`