a).(0.6)^5 : (0.2)^6 b). 2^7.9^3:6^5.8^2 c).6^3+3.6^2+3^3:-13 ( Bài 37 SGK Lớp 7 trang 22 ) Giúp mik nhé 07/07/2021 Bởi Kylie a).(0.6)^5 : (0.2)^6 b). 2^7.9^3:6^5.8^2 c).6^3+3.6^2+3^3:-13 ( Bài 37 SGK Lớp 7 trang 22 ) Giúp mik nhé
Bạn tham khảo nhé!$a)$ $\dfrac{4^{2} . 4^{3}}{2^{10}}$$=$ $\dfrac{(2^{2})^{2} . (2^{2})^{3}}{2^{10}}$$=$ $\dfrac{2^{4} . 2^{6}}{2^{10}}$$=$ $\dfrac{2^{10} }{2^{10}}$$=$ $1$$b)$ $\dfrac{(0.6)^{5}}{(0.2)^{6}}$$=$ $\dfrac{(0.2 . 3)^{5}}{(0.2)^{6}}$$=$ $\dfrac{0.2^{5} . 3^{5}}{(0.2)^{6}}$$=$ $\dfrac{1 . 3^{5}}{0.2}$$=$ $\dfrac{243}{0.2}$$c)$ $\dfrac{2^{7} . 9^{3}}{6^{5} . 8^{2}}$ $=$ $\dfrac{2^{7} . (3^{2})^{3}}{(2.3)^{5} . (2^{3})^{2}}$$=$ $\dfrac{2^{7} . 3^{6}}{2^{5} . 3^{5} . 2^{6}}$$=$ $\dfrac{2^{7} . 3}{2^{11} . 1 . }$$=$ $\dfrac{1. 3}{2^{4} . 1 . }$$=$ $\dfrac{3}{16}$$d)$ $\dfrac{6^{3} + 3 . 6^{2} + 3^{3}}{-13}$$=$ $\dfrac{6^{2} . (6+3) +27 }{-13}$$=$ $\dfrac{6^{2} . 9 +27 }{-13}$ $=$ $\dfrac{6^{2} . 9 + 9 . 3 }{-13}$$=$ $\dfrac{9 . (6^{2} + 3)}{-13}$ $=$ $\dfrac{9 . 39}{-13}$$=$ $-27$$FbBinhne2k88$ Bình luận
Đáp án: Giải thích các bước giải: `a) (0,6)^5/(0,2)^6= (0,2. 3)^5/(0,2)^{5+ 1}` `= (0,2)^5. 3^5/(0,2)^{5. 0,2}` `= 3^5/{0,2}= 243/{0,2}` `= 1215` `b) {2^7. 9^3}/{6^5. 8^2}` `= {2^7. (3^2)^3}/{(2. 3)^5. (2^3)^2}= {2^. 3^{2. 3}}/{2^5. 3^5. 2^{3. 2}}= {2^7. 3^6}/{2^5. 3^5. 2^6}= {2^7. 3^6}/{2^11. 3^5}= {3^2^4= 3}/16` `c) [6^3+ 3. 6^2+ 3^3}/-13` `= 216+ 108+ 27/-13` `= 351/-13` `= -27` Câu `d)` là cahs sễ hiểu nhất nhé! Bình luận
Bạn tham khảo nhé!
$a)$ $\dfrac{4^{2} . 4^{3}}{2^{10}}$
$=$ $\dfrac{(2^{2})^{2} . (2^{2})^{3}}{2^{10}}$
$=$ $\dfrac{2^{4} . 2^{6}}{2^{10}}$
$=$ $\dfrac{2^{10} }{2^{10}}$
$=$ $1$
$b)$ $\dfrac{(0.6)^{5}}{(0.2)^{6}}$
$=$ $\dfrac{(0.2 . 3)^{5}}{(0.2)^{6}}$
$=$ $\dfrac{0.2^{5} . 3^{5}}{(0.2)^{6}}$
$=$ $\dfrac{1 . 3^{5}}{0.2}$
$=$ $\dfrac{243}{0.2}$
$c)$ $\dfrac{2^{7} . 9^{3}}{6^{5} . 8^{2}}$
$=$ $\dfrac{2^{7} . (3^{2})^{3}}{(2.3)^{5} . (2^{3})^{2}}$
$=$ $\dfrac{2^{7} . 3^{6}}{2^{5} . 3^{5} . 2^{6}}$
$=$ $\dfrac{2^{7} . 3}{2^{11} . 1 . }$
$=$ $\dfrac{1. 3}{2^{4} . 1 . }$
$=$ $\dfrac{3}{16}$
$d)$ $\dfrac{6^{3} + 3 . 6^{2} + 3^{3}}{-13}$
$=$ $\dfrac{6^{2} . (6+3) +27 }{-13}$
$=$ $\dfrac{6^{2} . 9 +27 }{-13}$
$=$ $\dfrac{6^{2} . 9 + 9 . 3 }{-13}$
$=$ $\dfrac{9 . (6^{2} + 3)}{-13}$
$=$ $\dfrac{9 . 39}{-13}$
$=$ $-27$
$FbBinhne2k88$
Đáp án:
Giải thích các bước giải:
`a) (0,6)^5/(0,2)^6= (0,2. 3)^5/(0,2)^{5+ 1}`
`= (0,2)^5. 3^5/(0,2)^{5. 0,2}`
`= 3^5/{0,2}= 243/{0,2}`
`= 1215`
`b) {2^7. 9^3}/{6^5. 8^2}`
`= {2^7. (3^2)^3}/{(2. 3)^5. (2^3)^2}= {2^. 3^{2. 3}}/{2^5. 3^5. 2^{3. 2}}= {2^7. 3^6}/{2^5. 3^5. 2^6}= {2^7. 3^6}/{2^11. 3^5}= {3^2^4= 3}/16`
`c) [6^3+ 3. 6^2+ 3^3}/-13`
`= 216+ 108+ 27/-13`
`= 351/-13`
`= -27`
Câu `d)` là cahs sễ hiểu nhất nhé!