a).(0.6)^5 : (0.2)^6 b). 2^7.9^3:6^5.8^2 c).6^3+3.6^2+3^3:-13 ( Bài 37 SGK Lớp 7 trang 22 ) Giúp mik nhé

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1. Bạn tham khảo nhé!
   $a)$ $\dfrac{4^{2} . 4^{3}}{2^{10}}$
   $=$ $\dfrac{(2^{2})^{2} . (2^{2})^{3}}{2^{10}}$
   $=$ $\dfrac{2^{4} . 2^{6}}{2^{10}}$
   $=$ $\dfrac{2^{10} }{2^{10}}$
   $=$ $1$
   $b)$ $\dfrac{(0.6)^{5}}{(0.2)^{6}}$
   $=$ $\dfrac{(0.2  . 3)^{5}}{(0.2)^{6}}$
   $=$ $\dfrac{0.2^{5} . 3^{5}}{(0.2)^{6}}$
   $=$ $\dfrac{1 . 3^{5}}{0.2}$
   $=$ $\dfrac{243}{0.2}$
   $c)$ $\dfrac{2^{7} . 9^{3}}{6^{5} . 8^{2}}$ 
   $=$ $\dfrac{2^{7} . (3^{2})^{3}}{(2.3)^{5} . (2^{3})^{2}}$
   $=$ $\dfrac{2^{7} . 3^{6}}{2^{5} . 3^{5} . 2^{6}}$
   $=$ $\dfrac{2^{7} . 3}{2^{11} . 1 . }$
   $=$ $\dfrac{1. 3}{2^{4} . 1 . }$
   $=$ $\dfrac{3}{16}$
   $d)$ $\dfrac{6^{3} + 3 . 6^{2} + 3^{3}}{-13}$
   $=$ $\dfrac{6^{2} . (6+3) +27 }{-13}$
   $=$ $\dfrac{6^{2} . 9 +27 }{-13}$ 
   $=$ $\dfrac{6^{2} . 9 + 9 . 3  }{-13}$
   $=$ $\dfrac{9 . (6^{2} + 3)}{-13}$ 
   $=$ $\dfrac{9 . 39}{-13}$
   $=$ $-27$
   $FbBinhne2k88$

    

   Trả lời

2. Đáp án:

    

   Giải thích các bước giải:

    `a) (0,6)^5/(0,2)^6= (0,2. 3)^5/(0,2)^{5+ 1}`

   `= (0,2)^5. 3^5/(0,2)^{5. 0,2}`

   `= 3^5/{0,2}= 243/{0,2}`

   `= 1215`

   `b) {2^7. 9^3}/{6^5. 8^2}`

   `= {2^7. (3^2)^3}/{(2. 3)^5. (2^3)^2}= {2^. 3^{2. 3}}/{2^5. 3^5. 2^{3. 2}}= {2^7. 3^6}/{2^5. 3^5. 2^6}= {2^7. 3^6}/{2^11. 3^5}= {3^2^4= 3}/16`

   `c) [6^3+ 3. 6^2+ 3^3}/-13`

   `= 216+ 108+ 27/-13`

   `= 351/-13`

   `= -27`

   Câu `d)` là cahs sễ hiểu nhất nhé!

   Trả lời