A, ( x-8.25 ).4=0. B, ( x-50 ).4-3=97 C, 8.( 22-x) =24. D, ( x:3-3 )(x:6-6 )=0 E, 334-( x. 3+20 )=284. G, 4x+5x-x=128 Giú

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1. Giải thích các bước giải:

   Ta có:

   \(\begin{array}{l}
   a,\\
   \left( {x – 8.25} \right).4 = 0\\
    \Leftrightarrow x – 8.25 = 0\\
    \Leftrightarrow x – 200 = 0\\
    \Leftrightarrow x = 200\\
   b,\\
   \left( {x – 50} \right).4 – 3 = 97\\
    \Leftrightarrow \left( {x – 50} \right).4 = 3 + 97\\
    \Leftrightarrow \left( {x – 50} \right).4 = 100\\
    \Leftrightarrow x – 50 = 100:4\\
    \Leftrightarrow x – 50 = 25\\
    \Leftrightarrow x = 50 + 25\\
    \Leftrightarrow x = 75\\
   c,\\
   8.\left( {22 – x} \right) = 24\\
    \Leftrightarrow 22 – x = 24:8\\
    \Leftrightarrow 22 – x = 3\\
    \Leftrightarrow x = 22 – 3\\
    \Leftrightarrow x = 19\\
   d,\\
   \left( {x:3 – 3} \right).\left( {x:6 – 6} \right) = 0\\
    \Leftrightarrow \left[ \begin{array}{l}
   x:3 – 3 = 0\\
   x:6 – 6 = 0
   \end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
   x:3 = 3\\
   x:6 = 6
   \end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
   x = 9\\
   x = 36
   \end{array} \right.\\
   e,\\
   334 – \left( {x.3 + 20} \right) = 284\\
    \Leftrightarrow x.3 + 20 = 334 – 284\\
    \Leftrightarrow 3x + 20 = 50\\
    \Leftrightarrow 3x = 50 – 20\\
    \Leftrightarrow 3x = 30\\
    \Leftrightarrow x = 30:3\\
    \Leftrightarrow x = 10\\
   g,\\
   4x + 5x – x = 128\\
    \Leftrightarrow x.\left( {4 + 5 – 1} \right) = 128\\
    \Leftrightarrow x.8 = 128\\
    \Leftrightarrow x = 128:8\\
    \Leftrightarrow x = 16
   \end{array}\) 

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