A= (x+y-4) – (x-y+1) + (x-5) B= (a-b-c+d) -(b-c-d) – (a-b-d) 06/12/2021 Bởi Aaliyah A= (x+y-4) – (x-y+1) + (x-5) B= (a-b-c+d) -(b-c-d) – (a-b-d)
$A=(x+y-4)-(x-y+1)+(x-5)$ $A=x+y-4-x+y-1+x-5$ $A=(x-x+x)+(y+y)+(-4-1-5)$ $A=x+2y-10$ $B=(a-b-c+d)-(b-c-d)-(a-b-d)$ $B=a-b-c+d-b+c+d-a+b+d$ $B=(a-a)+(-b-b+b)+(-c+c)+(d+d+d)$ $B=3d-b$ Bình luận
$a) A=(x+y-4)-(x-y+1)+(x-5)$$A=x+y-4-x+y-1+x-5$ $A=(x-x+x)+(y+y)+(-4-1-5)$ $A=x+2y-10$ $b) B=(a-b-c+d)-(b-c-d)-(a-b-d)$ $B=a-b-c+d-b+c+d-a+b+d$ $B=(a-a)+(-b-b+b)+(-c+c)+(d+d+d)$ $B=3d-b$ Chúc Bạn Học Tốt !!! Bình luận
$A=(x+y-4)-(x-y+1)+(x-5)$
$A=x+y-4-x+y-1+x-5$
$A=(x-x+x)+(y+y)+(-4-1-5)$
$A=x+2y-10$
$B=(a-b-c+d)-(b-c-d)-(a-b-d)$
$B=a-b-c+d-b+c+d-a+b+d$
$B=(a-a)+(-b-b+b)+(-c+c)+(d+d+d)$
$B=3d-b$
$a) A=(x+y-4)-(x-y+1)+(x-5)$
$A=x+y-4-x+y-1+x-5$
$A=(x-x+x)+(y+y)+(-4-1-5)$
$A=x+2y-10$
$b) B=(a-b-c+d)-(b-c-d)-(a-b-d)$
$B=a-b-c+d-b+c+d-a+b+d$
$B=(a-a)+(-b-b+b)+(-c+c)+(d+d+d)$
$B=3d-b$
Chúc Bạn Học Tốt !!!