A= (x+y-4) – (x-y+1) + (x-5) B= (a-b-c+d) -(b-c-d) – (a-b-d)

0 bình luận về “A= (x+y-4) – (x-y+1) + (x-5) B= (a-b-c+d) -(b-c-d) – (a-b-d)”

1. $A=(x+y-4)-(x-y+1)+(x-5)$

   $A=x+y-4-x+y-1+x-5$

   $A=(x-x+x)+(y+y)+(-4-1-5)$

   $A=x+2y-10$

   $B=(a-b-c+d)-(b-c-d)-(a-b-d)$

   $B=a-b-c+d-b+c+d-a+b+d$

   $B=(a-a)+(-b-b+b)+(-c+c)+(d+d+d)$

   $B=3d-b$

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2. $a) A=(x+y-4)-(x-y+1)+(x-5)$
   $A=x+y-4-x+y-1+x-5$

   $A=(x-x+x)+(y+y)+(-4-1-5)$

   $A=x+2y-10$

   $b) B=(a-b-c+d)-(b-c-d)-(a-b-d)$

   $B=a-b-c+d-b+c+d-a+b+d$

   $B=(a-a)+(-b-b+b)+(-c+c)+(d+d+d)$

   $B=3d-b$

   Chúc Bạn Học Tốt !!!

   Trả lời