bài 1. 5x-2/3 = 5-3x/2 10x+3/12= 1+ 6+8x/9 7/8x – 5 ( x-9) = 20x + 1.5/6 bài 2. 1/x+1 – 5/x-2= 15/( x+1)(2-x) 1/2x-3 – 3/x( 2x-3)= 5/x 6/x-1 – 4/x-3=

bài 1. 5x-2/3 = 5-3x/2
10x+3/12= 1+ 6+8x/9
7/8x – 5 ( x-9) = 20x + 1.5/6
bài 2. 1/x+1 – 5/x-2= 15/( x+1)(2-x)
1/2x-3 – 3/x( 2x-3)= 5/x
6/x-1 – 4/x-3= 8/2x-6
3/(x-1)(x-2) + 2/(x-2)(x-3) = 1/(x-2)(x-3)
1/x-2 + 5/x+1= 3/2-x
5x/2x+2 + 1= 6/x+1
x+1/x-1 – x-1/ x+1= 4/x^2-1
3x/x-2 – x/x-5= 3x/(x-2)(5-x)

0 bình luận về “bài 1. 5x-2/3 = 5-3x/2 10x+3/12= 1+ 6+8x/9 7/8x – 5 ( x-9) = 20x + 1.5/6 bài 2. 1/x+1 – 5/x-2= 15/( x+1)(2-x) 1/2x-3 – 3/x( 2x-3)= 5/x 6/x-1 – 4/x-3=”

  1. `( 5x-2)/3 = (5-3x)/2`

    `<=>2(5x-2)=3(5-3x)`

    `<=>19x=19`

    `<=>x=1`

    `(10x+3)/12= 1+ (6+8x)/9`

    `<=>3(10+3)=36+8(3+4x)`

    `<=>2x+60=9`

    `<=>x=-51/2`

    `7/8x – 5 ( x-9) = 20x + 1.5/6`

    `<=>7x-40x+360=160x+2`

    `<=>358=193x`

    `<=>x=358/193`

    `1/(x+1 )- 5/(x-2)= 15/(( x+1)(2-x))`

    `<=>(x-2)(2-x)-5(x+1)(2-x)=15(x-2)`

    `<=>x-4x^2+14+15x-30=0`

    `<=>x-2=0`

    `<=>x=2(l)`

    `2x-3 – 3/(x( 2x-3))= 5/x`

    `<=>2x^2(2x-3)-3x(2x-3)-3=5(2x-3)`

    `<=>4x^3-12x^2-x+12=0`

    `(5x)/(2x+2) + 1= 6/(x+1)`

    `<=>5x+2(x+1)=12`

    `<=>7x+2=12`

    `<=>x=10/7`

    Vậy …

    Bình luận

Viết một bình luận