cho a/b = c/d . CM : a) a/a-b = c/c-d b/) a/b =a+c/b+d c)a/3a+b = c/3c+d

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cho a/b = c/d . CM :
a) a/a-b = c/c-d
b/) a/b =a+c/b+d
c)a/3a+b = c/3c+d

0 bình luận về “cho a/b = c/d . CM : a) a/a-b = c/c-d b/) a/b =a+c/b+d c)a/3a+b = c/3c+d”

1. thienthanh

Đáp án:

$\begin{array}{l} \dfrac{a}{b} = \dfrac{c}{d} = k \Rightarrow \left\{ \begin{array}{l} a = b.k\\ c = d.k \end{array} \right.\\ a)\dfrac{a}{{a – b}} = \dfrac{{b.k}}{{b.k – b}} = \dfrac{{b.k}}{{b.\left( {k – 1} \right)}} = \dfrac{k}{{k – 1}}\\ \dfrac{c}{{c – d}} = \dfrac{{d.k}}{{dk – d}} = \dfrac{{dk}}{{d.\left( {k – 1} \right)}} = \dfrac{k}{{k – 1}}\\ \Rightarrow \dfrac{a}{{a – b}} = \dfrac{c}{{c – d}}\\ b)\\ \dfrac{{a + c}}{{b + d}} = \dfrac{{b.k + d.k}}{{b + d}} = \dfrac{{k.\left( {b + d} \right)}}{{b + d}} = k\\ \Rightarrow \dfrac{a}{b} = \dfrac{{a + c}}{{b + d}} = k\\ c)\\ \dfrac{a}{{3a + b}} = \dfrac{{b.k}}{{3bk + b}} = \dfrac{k}{{3k + 1}}\\ \dfrac{c}{{3c + d}} = \dfrac{{dk}}{{3dk + d}} = \dfrac{k}{{3k + 1}}\\ \Rightarrow \dfrac{a}{{3a + b}} = \dfrac{c}{{3c + d}} \end{array}$

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