Toán $\frac{ √2+ √3+ √6+ √8+ √16}{√2+ √3+ √4 }$ 01/10/2021 By Valentina $\frac{ √2+ √3+ √6+ √8+ √16}{√2+ √3+ √4 }$
\(\dfrac{\sqrt 2+\sqrt3+\sqrt 6+\sqrt 8+4}{\sqrt2+\sqrt 3+\sqrt 4}\) \(=\dfrac{\sqrt 2+\sqrt3+2+\sqrt 6+\sqrt 8+2}{\sqrt2+\sqrt 3+\sqrt 4}\) \(=\dfrac{\sqrt 2+\sqrt3+\sqrt 4+\sqrt 6+\sqrt 8+\sqrt 4}{\sqrt2+\sqrt 3+\sqrt 4}\) \(=1+\dfrac{\sqrt 2(\sqrt3+\sqrt4+\sqrt2)}{\sqrt2+\sqrt 3+\sqrt 4}\) \(=1+1\) \(=2\) Trả lời
$\frac{√2+√3+√6+√8+√16}{√2+√3+√4}$ =$\frac{√2+√3+√6+√8+4}{√2+√3+√4}$ =$\frac{√2+√3+2}{√2+√3+√4}$ +$\frac{2+√6+√8}{√2+√3+√4}$ =1+$\frac{√2(√2+√3+√4)}{√2+√3+√4}$ =1+√2 Trả lời
\(\dfrac{\sqrt 2+\sqrt3+\sqrt 6+\sqrt 8+4}{\sqrt2+\sqrt 3+\sqrt 4}\)
\(=\dfrac{\sqrt 2+\sqrt3+2+\sqrt 6+\sqrt 8+2}{\sqrt2+\sqrt 3+\sqrt 4}\)
\(=\dfrac{\sqrt 2+\sqrt3+\sqrt 4+\sqrt 6+\sqrt 8+\sqrt 4}{\sqrt2+\sqrt 3+\sqrt 4}\)
\(=1+\dfrac{\sqrt 2(\sqrt3+\sqrt4+\sqrt2)}{\sqrt2+\sqrt 3+\sqrt 4}\)
\(=1+1\)
\(=2\)
$\frac{√2+√3+√6+√8+√16}{√2+√3+√4}$
=$\frac{√2+√3+√6+√8+4}{√2+√3+√4}$
=$\frac{√2+√3+2}{√2+√3+√4}$ +$\frac{2+√6+√8}{√2+√3+√4}$
=1+$\frac{√2(√2+√3+√4)}{√2+√3+√4}$
=1+√2