M=( 2+ √ √2 + 1)(2- √ √2- 1) √11+6 √2 N= √2 + √8+ √32 + √128 – √162 – √72

0 bình luận về “M=( 2+ √ √2 + 1)(2- √ √2- 1) √11+6 √2 N= √2 + √8+ √32 + √128 – √162 – √72”

1. `M = (2+\sqrt2 + 1)(2 – \sqrt2 – 1). \sqrt11 + 6\sqrt2`

   `= [(2+(\sqrt2+1)][2-(\sqrt2+1)] . \sqrt11 + 6\sqrt2`

   `= (2^2 – (\sqrt2+1)^2) . \sqrt11 + 6\sqrt2`

   `= ( 1- 2\sqrt2) . \sqrt11 + 6\sqrt2`

   `= -2\sqrt22 + \sqrt11 + 6\sqrt2`

   `N = \sqrt2 + \sqrt8 + \sqrt32 + \sqrt128 – \sqrt162 – \sqrt72`

   `= \sqrt2 + 2\sqrt2 + 4\sqrt2 + 8\sqrt2 – 9\sqrt2 – 6\sqrt2`

   `= 0`

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