m = “2^2019 – (2^2018 + 2^2017 + 2^2016 + …. + 2^1 + 3)” CẦU LÀM NHANH TRONG 5′ Ạ!!!!!!!!!!!

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1. `M = 2^2019 – (2^2018 + 2^2017 + … + 2^1 + 3 )`

   `=> M= 2^2019 – 2^2018 – 2^2017 – … – 2^1 -3`

   `=> 2M = 2(2^2019 – 2^2018 – 2^2017 – …. – 2^2 – 3 )`

   `=> 2M = 2^2020 – 2^2019 – 2^2018 – … – 2^3 – 6`

   `=> 2M – M = ( 2^2020 – 2^2019 – 2^2018 – … – 2^2 – 6) – (2^2019 – 2^2018 – 2^2017 – … – 2^1-3)`

   `=> M =  2^2020 – 2^2019 – 2^2018 – … – 2^3 – 6 – 2^2019 + 2^2018 + 2^2017 + … + 2^2 + 3`

   `=> M = 2^2020 – 2^2019 – 2^2019 – 6 +3 + 2`

   `=> M = 2^2019 . 2 – 2^2019 – 2^2019 – 6 +3 +2`

   `=> M = 2^2019 ( 2 – 1) – 2^2019 -1`

   `=> M = 2^2019 – 2^2019 – 1`

   `=> M = -1`

    

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2. Đáp án + Giải thích các bước giải:

   `M = 2^2019 – (2^2018 + 2^2017 + 2^2016 + …. + 2^1 + 3)`

   `=>M = 2^2019 – 2^2018 – 2^2017 – 2^2016 – …. – 2^1 – 3`

   `=> 2M = 2^2020 – 2^2019 – 2^2018 – 2^2017 – …. – 2^2 – 6`

   `=> 2M-M = 2^2020 – 2^2019 – 2^2018 – 2^2017 – …. – 2^2 – 6 – 2^2019 + 2^2018 + 2^2017 + 2^2016 + …. + 2^1 + 3`

   `=> M = 2^2020 – 2^2019 – 2^2019 + 2 + 3 – 6 `

   `=> M = 2^2020 – 2^2020 – 1`

   `=> M = – 1`

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