P=$\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{15}}$
Q=[0,8.7+(0.8) ²].[1,25.7-$\frac{4}{5}$.1,25]+31,64
HELP ME ω ω ω ω ω
P=$\frac{0,75-0,6+\frac{3}{7}+\frac{3}{13}}{2,75-2,2+\frac{11}{7}+\frac{11}{15}}$
Q=[0,8.7+(0.8) ²].[1,25.7-$\frac{4}{5}$.1,25]+31,64
HELP ME ω ω ω ω ω
Đáp án:
Q=80
Giải thích các bước giải:
\(\begin{array}{l}
P = \left( {\dfrac{3}{4} – \dfrac{3}{5} + \dfrac{3}{7} + \dfrac{3}{{15}}} \right):\left( {\dfrac{{11}}{4} – \dfrac{{11}}{5} + \dfrac{{11}}{7} + \dfrac{{11}}{{15}}} \right)\\
= 3\left( {\dfrac{1}{4} – \dfrac{1}{5} + \dfrac{1}{7} + \dfrac{1}{{15}}} \right):11\left( {\dfrac{1}{4} – \dfrac{1}{5} + \dfrac{1}{7} + \dfrac{1}{{15}}} \right)\\
= \dfrac{{3\left( {\dfrac{1}{4} – \dfrac{1}{5} + \dfrac{1}{7} + \dfrac{1}{{15}}} \right)}}{{11\left( {\dfrac{1}{4} – \dfrac{1}{5} + \dfrac{1}{7} + \dfrac{1}{{15}}} \right)}} = \dfrac{3}{{11}}\\
Q = \left[ {\dfrac{4}{5}.7 + \dfrac{{16}}{{25}}} \right].\left( {\dfrac{5}{4}.7 – \dfrac{4}{5}.\dfrac{5}{4}} \right) + \dfrac{{791}}{{25}}\\
= \left( {\dfrac{{28}}{5} + \dfrac{{16}}{{25}}} \right).\left( {\dfrac{{35}}{4} – 1} \right) + \dfrac{{791}}{{25}}\\
= \dfrac{{156}}{{25}}.\dfrac{{31}}{4} + \dfrac{{791}}{{25}} = \dfrac{{1209}}{{25}} + \dfrac{{791}}{{25}} = 80
\end{array}\)
( Đoạn cuối câu P ở tử hoặc ở mẫu t nghĩ đề sẽ để \({\dfrac{3}{{15}}}\) và \({\dfrac{{11}}{{15}}}\) giống nhau như vậy mới có quy tắc làm bạn nhé)