phân tích đa thức thành nhân tử a.5x^2-5xy-10x+10y b.4x^2+8xy-3x-6y c.2x+2y-x(x+y) d.x(x-y)+(x-y) 01/07/2021 Bởi Adalynn phân tích đa thức thành nhân tử a.5x^2-5xy-10x+10y b.4x^2+8xy-3x-6y c.2x+2y-x(x+y) d.x(x-y)+(x-y)
$a)_{}$ $5x^2-5xy-10x+10y_{}$ $⇔x.(x^2-xy-2x+2y)_{}$ $⇔5. [ x.(x-y)-2.(x-y)]_{}$ $⇔5.(x-y)(x-2)_{}$ $b)_{}$ $4x^2+8xy-3x-6y_{}$ $⇔4x.(x+2y)-3.(x+2y)_{}$ $⇔(x+2y)(4x-3)_{}$ $c)_{}$ $2x+2y-x.(x+y)_{}$ $⇔2.(x+y)-x.(x+y)_{}$ $⇔(x+y)(2-x)_{}$ $d)_{}$ $x.(x-y)+(x-y)_{}$ $⇔(x+1)(x-y)_{}$ Bình luận
$a)_{}$ $5x^2-5xy-10x+10y_{}$
$⇔x.(x^2-xy-2x+2y)_{}$
$⇔5. [ x.(x-y)-2.(x-y)]_{}$
$⇔5.(x-y)(x-2)_{}$
$b)_{}$ $4x^2+8xy-3x-6y_{}$
$⇔4x.(x+2y)-3.(x+2y)_{}$
$⇔(x+2y)(4x-3)_{}$
$c)_{}$ $2x+2y-x.(x+y)_{}$
$⇔2.(x+y)-x.(x+y)_{}$
$⇔(x+y)(2-x)_{}$
$d)_{}$ $x.(x-y)+(x-y)_{}$
$⇔(x+1)(x-y)_{}$
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