Tìm x
(34.2x).(2x-6) = 0
(2019-x).(3x-12) = 0
57.(9x-27) = 0
3.(x+7)-15 = 27
25+3.(5-x) = 27
Tìm x (34.2x).(2x-6) = 0 (2019-x).(3x-12) = 0 57.(9x-27) = 0 3.(x+7)-15 = 27 25+3.(5-x) = 27
By Audrey
By Audrey
Tìm x
(34.2x).(2x-6) = 0
(2019-x).(3x-12) = 0
57.(9x-27) = 0
3.(x+7)-15 = 27
25+3.(5-x) = 27
Lời giải chi tiết:
`a,(34*2x)(2x-6)=0`
`<=>34*2x=0` hoặc `2x-6=0`
`<=>x=0` hoặc `x=3`
`b,(2019-x)(3x-12)=0`
`<=>x=2019` hoặc `x=4`
`c,57(9x-27)=0`
`<=>9x-27=0`
`<=>9x=27`
`<=>x=3`
`d,3(x+7)-15=27`
`<=>3(x+7)=42`
`<=>x+7=14`
`<=>x=7`
`e,25+3(5-x)=27`
`<=>3(5-x)=2`
`<=>5-x=2/3`
`<=>x=2/15`
Vậy ……………………
`a,(34*2x)(2x-6)=0`
`<=>34*2x=0` hoặc `2x-6=0`
`<=>x=0` hoặc `x=3`
Vậy ….
`b,(2019-x)(3x-12)=0`
`<=>x=2019` hoặc `x=4`
Vậy …..
`c,57(9x-27)=0`
`<=>9x-27=0`
`<=>x=3`
Vậy ….
`d,3(x+7)-15=27`
`<=>3(x+7)=42`
`<=>x+7=14`
`<=>x=7`
Vậy …….
`e,25+3(5-x)=27`
`<=>3(5-x)=2`
`<=>5-x=2/3`
`<=>x=2/15`
Vậy ….