tìm x a/(2x ²-3x)=0 b/4+3x ²/x-3 – 2x+2x ²/x-3 + 2x-13/x-3 =0 càn gấp

a) $2x^2-3x=0$

$⇔x.(2x-3)=0$

$⇔$\(\left[ \begin{array}{l}x=0\\2x-3=0\end{array} \right.\) 

$⇔$\(\left[ \begin{array}{l}x=0\\2x=3\end{array} \right.\) 

$⇔$\(\left[ \begin{array}{l}x=0\\x=\dfrac{3}{2}\end{array} \right.\) 

b) $\dfrac{4+3x^2}{x-3}-\dfrac{2x+2x^2}{x-3}+\dfrac{2x-13}{x-3}=0$

$⇔\dfrac{4+3x^2-2x-2x^2+2x-13}{x-3}=0$

$⇔\dfrac{x^2-9}{x-3}=0$

$⇔\dfrac{(x-3)(x+3)}{x-3}=0$

$⇔x+3=0$

$⇔x=-3$