Tìm x : a) -5/9 + 3/19 < x/19 ≤ 13/19 + -11/19 b) -7/8+5/6 ≤ x/24 ≤ 5/8+-5/12 ( mik đag cần gáp, giải giúp mik vs ạ0 21/11/2021 Bởi Adalyn Tìm x : a) -5/9 + 3/19 < x/19 ≤ 13/19 + -11/19 b) -7/8+5/6 ≤ x/24 ≤ 5/8+-5/12 ( mik đag cần gáp, giải giúp mik vs ạ0
Đáp án: $a) x=\{-1,0,1,2\}\\b) x=\{-1,0,1,2,3,4,5\}$ Giải thích các bước giải: $a)\frac{-5}{19}+\frac{3}{19}<\frac{x}{19}\leq \frac{13}{19}+\frac{-11}{19}\\\Leftrightarrow 19.\left (\frac{-5}{19}+\frac{3}{19} \right )<19.\frac{x}{19}\leq 19.\left (\frac{13}{19}+\frac{-11}{19} \right )\\\Leftrightarrow -5+3<x\leq 13-11\\\Leftrightarrow -2<x\leq 2\\\Rightarrow x=\{-1,0,1,2\}\\b) \frac{-7}{8}+\frac{5}{6}\leq \frac{x}{24}\leq \frac{5}{8}+\frac{-5}{12}\\\Leftrightarrow 24.\left (\frac{-7}{8}+\frac{5}{6} \right )\leq 24.\frac{x}{24}\leq 24.\left (\frac{5}{8}+\frac{-5}{12} \right )\\\Leftrightarrow -21+20\leq x\leq 15-10\\\Leftrightarrow -1\leq x\leq 5\\\Rightarrow x=\{-1,0,1,2,3,4,5\}$ Bình luận
Đáp án:
$a) x=\{-1,0,1,2\}\\
b) x=\{-1,0,1,2,3,4,5\}$
Giải thích các bước giải:
$a)\frac{-5}{19}+\frac{3}{19}<\frac{x}{19}\leq \frac{13}{19}+\frac{-11}{19}\\
\Leftrightarrow 19.\left (\frac{-5}{19}+\frac{3}{19} \right )<19.\frac{x}{19}\leq 19.\left (\frac{13}{19}+\frac{-11}{19} \right )\\
\Leftrightarrow -5+3<x\leq 13-11\\
\Leftrightarrow -2<x\leq 2\\
\Rightarrow x=\{-1,0,1,2\}\\
b) \frac{-7}{8}+\frac{5}{6}\leq \frac{x}{24}\leq \frac{5}{8}+\frac{-5}{12}\\
\Leftrightarrow 24.\left (\frac{-7}{8}+\frac{5}{6} \right )\leq 24.\frac{x}{24}\leq 24.\left (\frac{5}{8}+\frac{-5}{12} \right )\\
\Leftrightarrow -21+20\leq x\leq 15-10\\
\Leftrightarrow -1\leq x\leq 5\\
\Rightarrow x=\{-1,0,1,2,3,4,5\}$