Tìm x :  a) -5/9 + 3/19 < x/19 ≤ 13/19 + -11/19 b) -7/8+5/6 ≤ x/24 ≤ 5/8+-5/12 ( mik đag cần gáp, giải giúp mik vs ạ0

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1. Đáp án:

    $a) x=\{-1,0,1,2\}\\
   b)  x=\{-1,0,1,2,3,4,5\}$

   Giải thích các bước giải:

   $a)\frac{-5}{19}+\frac{3}{19}<\frac{x}{19}\leq \frac{13}{19}+\frac{-11}{19}\\
   \Leftrightarrow 19.\left (\frac{-5}{19}+\frac{3}{19}  \right )<19.\frac{x}{19}\leq 19.\left (\frac{13}{19}+\frac{-11}{19}  \right )\\
   \Leftrightarrow -5+3<x\leq 13-11\\
   \Leftrightarrow -2<x\leq 2\\
   \Rightarrow x=\{-1,0,1,2\}\\
   b) \frac{-7}{8}+\frac{5}{6}\leq \frac{x}{24}\leq \frac{5}{8}+\frac{-5}{12}\\
   \Leftrightarrow 24.\left (\frac{-7}{8}+\frac{5}{6}  \right )\leq 24.\frac{x}{24}\leq 24.\left (\frac{5}{8}+\frac{-5}{12}  \right )\\
   \Leftrightarrow -21+20\leq x\leq 15-10\\
   \Leftrightarrow -1\leq x\leq 5\\
   \Rightarrow x=\{-1,0,1,2,3,4,5\}$ 

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