Tính nhanh a) ( 1+ 3 + 5 + ……… + 99 ) . ( 36 . 333 – 108.111) b) (37.13-13) : (24 + 37.12)

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1. $ a) ( 1+ 3 + 5 + ……… + 99 ) . ( 36 . 333 – 108.111)$

   $= ( 1+ 3 + 5 + ……… + 99 ) . (36 . 3 . 111 – 108 .111)$

   $= ( 1+ 3 + 5 + ……… + 99 ) . (108.111 – 108 .111)$

   $= ( 1+ 3 + 5 + ……… + 99 ).0$

   $= 0$

   $b)(37.13-13) : (24 + 37.12)$

   $= (37.12 + 37 – 13) : (24 + 37.12)$

   $= (37.12 +24) : (24 + 37.12)$

   $= 1$

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2. Đáp án:

    

   Giải thích các bước giải:

    a)

      ( 1+ 3 + 5 + ……… + 99 ) . ( 36 . 333 – 108.111)

   = ( 1+ 3 + 5 + ……… + 99 ) . ( 36 . 3 . 111 – 108.111)

   = ( 1+ 3 + 5 + ……… + 99 ) . ( 108 . 111 – 108 . 111)

   = ( 1+ 3 + 5 + ……… + 99 ) . 0

   = 0

   b)

       (37 . 13 – 13) : (24 + 37 . 12)

   = (37 . 13 – 13) : (37 – 13 + 37 . 12)

   = (37 . 13 – 13) : [37 . (12 + 1) – 13]

   = (37 . 13 – 13) : (37 . 13 – 13)

   = 1

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