Toán tính tổng A=1+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9+2^10 23/10/2021 By Raelynn tính tổng A=1+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9+2^10
Đáp án: `A=2^11-1` Giải thích các bước giải: `A=1+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9+2^10` `2A=2+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9+2^10+2^11` `2A-A=(2+2^2+2^3+…+2^11)-(1+2+2^2+…+2^10)` `A=2^11-1` Trả lời
@py `A=1+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9+2^(10)` `2A=2+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9+2^(10)+2^(11)` `2A-A=A=2^(11)-1` Trả lời
Đáp án:
`A=2^11-1`
Giải thích các bước giải:
`A=1+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9+2^10`
`2A=2+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9+2^10+2^11`
`2A-A=(2+2^2+2^3+…+2^11)-(1+2+2^2+…+2^10)`
`A=2^11-1`
@py
`A=1+2+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9+2^(10)`
`2A=2+2^2+2^3+2^4+2^5+2^6+2^7+2^8+2^9+2^(10)+2^(11)`
`2A-A=A=2^(11)-1`