Tính (x/y) ^3 -6(y-x/2)^2 + 12(y-x/2)-8 21/08/2021 Bởi Charlie Tính (x/y) ^3 -6(y-x/2)^2 + 12(y-x/2)-8
(x/y) ^3 -6(y-x/2)^2 + 12(y-x/2)-8 =x³/y³-6(y²-2xy+x/4)+12y-3x/2-8 =x³/y³-6y²+12xy-3x/2+12y-3x/2-8 =x³/y³-6y²+12xy-3x+12y-8 Bình luận
`(x/y)^3 – 6(y-x/2)^2 + 12(y-x/2)-8` `=[x³]/[y³]-6(y²-2xy+x/4)+12y-3x/2-8` `=[x³]/[y³]-6y²+12xy-3x+12y-8` Xin hay nhất ! Bình luận
(x/y) ^3 -6(y-x/2)^2 + 12(y-x/2)-8
=x³/y³-6(y²-2xy+x/4)+12y-3x/2-8
=x³/y³-6y²+12xy-3x/2+12y-3x/2-8
=x³/y³-6y²+12xy-3x+12y-8
`(x/y)^3 – 6(y-x/2)^2 + 12(y-x/2)-8`
`=[x³]/[y³]-6(y²-2xy+x/4)+12y-3x/2-8`
`=[x³]/[y³]-6y²+12xy-3x+12y-8`
Xin hay nhất !